A pinjointed fourbar linkage is shown in the figure below. The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and La = 3.5 in. Using the current position, 02 110°, the position analysis has determined that 0 = 209.21°. Currently, link 2 is traveling at 10 rad/s CW CO B. 8, =0 L, Figure 6.7 Four-bar linkage acceleration analysis The angular velocities of link 3 wz and and link 4 wa are: Select one: O a. w3 = -4.29 rad/s, wa = 4.81 rad/s O b. w3 = 2.7 rad/s, w4 = 3.428 rad/s O c. W3 = -4.29 rad/s, wa = -4.38 rad/s O d. wz = 3.589 rad/s, w = 4.81 rad/s %3!

Please all choose with explain

5. Estimate the sliding velocity d and the angular velocity @3 using instant center velocity analysis for the open configuration of the crank-slider linkage in Table P6-2 row g by drawing the linkage to scale and measuring lengths using a ruler and angles using a protractor. Link 2 Link 3 Offset 1.4 4 1 2 6 -3 3 8 2 3.5 10 1 20 -5 f 13 0 g 25 10 *Drawings of these linkages are in the PDF Problem Workbook folder. Row TDC04 a b с d e 002 Link 2 02 Y A LO 5 3 7 A 0₂ Link 3 Offset Slider position d 0₂ 45 60 -30 120 225 100 330 YA B 4 002 10 -12 -15 24 -50 -45 100 X 04= = 90° X

A general pinjointed fourbar linkage is shown in the figure below. It has the followings: The link lengths are L1 = 8.50 in., L2 = 3.00 in., L3 = 5.00 in. and L4 = 4.50 in. The values of θ1 = 0, θ2 = 60°, and θ4 = 119°. The angular velocity of link2 ω2 = 10 rad/s CCW. The angular velocities of link 3 ω3 and and link 4 ω4 are: Select one: a. ω3 = 5.29 rad/s CW, ω4 = 4.80 rad/s CCW b. ω3 = 5.29rad/s CW, ω4 = 6.14 rad/s CW c. ω3 = 3.94 rad/s CCW, ω4 = 4.8 rad/s CCW d. ω3 = 3.94 rad/s CCW, ω4 = 6.14 rad/s CCW

Consider an offset inverted four-bar slider crank mechanism as shown in the following figure. Determine the angular acceleration of link 3 given L2 = 6 cm, 0₂ = 60°, and other dimensions shown in the figure. 02 = = 70 rad/sec² CCW 0₂ = 90 rpm CW A 3 02 3.0 cm 10.0 cm 4 B3 on 3 B4 on 4

I want to explain where the numbers 6.2772 and -1.274 come from(are marked in red) just calculation for the two nb

P1 00:00 A 650.00 F 420.00 P B 450.00 P2 A four-bar mechanism is given in the below figure. Link P₁A and P₂B are made by steel and have uniform cross sections. The PAB section, which is a right triangle, made by aluminium. Link P₁A has rotational velocity and acceleration of 8 rad/s and 20 rad/s² (both counterclockwise), respectively. There is a horizontal force at P of F= 200 N. Given G₂, G3 and G4 are the centre of mass of the links P₁A, PAB and P₂B, respectively. The masses of the links P₁A, PAB and P₂B are in turn m₂ = 1 kg: m3 = 2 kg and m4 = 1.2 kg. The moment of inertia of the links P1A, PAB and P₂B are in turn IG2 = 0.08 kgm²; IG3 = 0.15 kgm² and IG4 = 0.1 kgm². Find all the forces acting on the joints at this instant.

What do crossed and open mean? Please explain exactly on this drawing only and when it is crossed and open? and When do we decrease 360 ​​and when do we increase 360? with all explination on the graph only i will give u good feedback please

A four-bar mechanism is used to transmit power to slider E. Link AC rotates counterclockwise at 100 rpm. A and B are fixed points. The following linkages are measured in cm: AC=35, AB=70, CD=45, BD=45, DE=40. Find the instantaneous velocity of slider E in cm/s 1.Draw the mechanism in appropriate scale on your paper2. Find the instantaneous linear velocity of C3. Find a point on your paper to draw the velocity polygon and scale the magnitude of the computed linearvelocity4. Use the relative velocity equation for finding the linearvelocity of D; ? = ? + ?? ? ?/?5. Remember that although the magnitudes are unknown, their directions can be identified6. Obtain the magnitudes of the unknown velocities from the velocity polygon7. For Link DE, repeat the process by using ? = ? + ??the line as much as needed8. Remember that E is a SLIDER therefore it can only goin the direction where its movement is not constrained? . Add the vector ? to the head of ? and extend?/? ?/??

1. Suppose a link that is held in a ball joint (spherical pair) at one end rotates with an instantaneous angular velocity. w = - i+j5 - k3 (rad/s) Find the instantaneous velocity of P, a point on the link defined by the radius vector r= 14 - j - k7 (mm).