Dynamics of a four-bar linkageI = 4.27x10 kg -m²M = 0.08kgM, = 0.26kgM = 0.18kgOA =0.08mAB = 0.26mI, =1.46 x 10 'kg-m²ANВС - 0.18mI = 4.86 x10 kg m²%3DOC = 0.18mg = 9.8m/s +BT=0.1N mhow was I(inertia) calculated? what is the formula?

Answered: Image /qna-images/answer/74cf844a-c2a2-4d93-a140-0576cf734318.jpg

Dynamics of a four-bar linkage I, = 4.27x10ʻkg-m² I, =1.46 x10 °kg-m² I, = 4.86x10“kg-m² OA=0.08m M = 0.08kg AB = 0.26m M, = 0.26kg BC = 0.18m M =0.18kg OC = 0.18m g = 9.8m/s² 4 B T=0.IN·m how was l(inertia) calculated? what is the formula?

Dynamics of a four-bar linkage I, = 4.27x10ʻkg-m² I, =1.46 x10 °kg-m² I, = 4.86x10“kg-m² OA=0.08m M = 0.08kg AB = 0.26m M, = 0.26kg BC = 0.18m M =0.18kg OC = 0.18m g = 9.8m/s² 4 B T=0.IN·m how was l(inertia) calculated? what is the formula?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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