Drill Practice: lab write-up Molarity of left-over ions 1. Suppose 100.0 mL of 0.100 M hydrochloric acid and 100.0 mL of 0.75 M lead (II) nitrate allowed to react to form solid to form lead (II) chloride and aqueous nitric acid. a. Write the balanced chemical reaction Pb(NO3)₂ -> Pb cl HGI t b. How many moles of precipitate are formed? + HNO3 c. Calculate the concentration of the spectator ions present after the reaction occu d. Calculate the molarity of the leftover ion.

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Drill Practice: lab write-up
Molarity of left-over ions
1. Suppose 100.0 mL of 0.100 M hydrochloric acid and 100.0 mL of 0.75 M lead (II) nitrate are
allowed to react to form solid to form lead (II) chloride and aqueous nitric acid.
a. Write the balanced chemical reaction
HG|
t
Pb (NO3)₂
b. How many moles of precipitate are formed?
→Pb cl
d. Calculate the molarity of the leftover ion.
+ HNO3
C. Calculate the concentration of the spectator ions present after the reaction occurs.
2.
An acid-base reaction is conducted where 100.0 mL of 0.300 M sulfuric acid is reacted with
100.0 mL of 0.700 M potassium hydroxide. Determine the concentration of each of the ions.
after reaction is complete.
Transcribed Image Text:Drill Practice: lab write-up Molarity of left-over ions 1. Suppose 100.0 mL of 0.100 M hydrochloric acid and 100.0 mL of 0.75 M lead (II) nitrate are allowed to react to form solid to form lead (II) chloride and aqueous nitric acid. a. Write the balanced chemical reaction HG| t Pb (NO3)₂ b. How many moles of precipitate are formed? →Pb cl d. Calculate the molarity of the leftover ion. + HNO3 C. Calculate the concentration of the spectator ions present after the reaction occurs. 2. An acid-base reaction is conducted where 100.0 mL of 0.300 M sulfuric acid is reacted with 100.0 mL of 0.700 M potassium hydroxide. Determine the concentration of each of the ions. after reaction is complete.
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