Drag and drop to get the output 13 12 11 10 if the input : 10 11 12 13 #3include #define SIZE 25 int main(){ int max, a, array[SIZE]; int *pointr; pointr = printf('\nEnter the size of array : "): scanf('%d", &max): printf(\nEnter %d integers into array: ", SIZE); for (a = 0: ; ++a) { scanf("%d", pointr); pointr Sarravfmay 11
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![Drag and drop to get the output : 13 12 11 10 if the
input : 10 11 12 13
#include<stdio.h>
#define SIZE 25
int main(){
int max, a, array[SIZE];
int *pointr;
pointr
printf("\nEnter the size of array : "):
scanf( %d", &max);
printf(\nEnter %d integers into array: ", SIZE);
for (a = 0:
: ++a) {
%3!
scanf("%d", pointr);
pointr = &array[max - 1]:
printf(\nElements of array in reverse order are : ");
for (
;a >= 0; a--) {
printf("\nElement %d is %d : ", a, *pointr);
-pointr
a< max
&array[0]
++pointr
a
max - 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F885070d0-a5c4-4e2f-933e-724d4d41d476%2Fb86827f6-01a7-48c5-a36b-387164a5f4ce%2Figj3w5w_processed.jpeg&w=3840&q=75)
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- Two dimension array in C:Create a two dimension array of integers that is 5 rows x 10 columns.Populate each element in the first 2 rows (using for loops) with the value 5.Populate each element of the last three rows (using for loops) with the value 7.Write code (using for loops) to sum all the elements of the first three columns and output thesum to the screen. without using #define#include using namespace std; main() { int num array[] = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; for (int n-1; n<-5;++n) { cout <« n<< * "; } return 0; Out put : 1 23 4 567 89 10 O Out put : 3 4 56789 10 O Out put : 2 3 45 67 89 10 11 O Out put : 1 2 3 456 Out put : 1 2 345 Not listed OTwo dimension array in C:Create a two dimension array of integers that is 5 rows x 10 columns.Populate each element in the first 2 rows (using for loops) with the value 5.Populate each element of the last three rows (using for loops) with the value 7.Write code (using for loops) to sum all the elements of the first three columns and output thesum to the screen.
- Drag and drop to get the output : 13 12 11 10 if the input : 10 11 12 13 #include #define SIZE 25 int main(){ int max, a, array[SIZE]; int "pointr; pointr printf(\nEnter the size of array : "); scanf("%d", &max); printf(\nEnter %d integers into array: , SIZE); for (a = 0: ; ++a) { scanf('%d", pointr); } pointr = &array[max - 1]: printf(\nElements of array in reverse order are : ); for :a >= 0; a-) { printf(\nElement %d is %d : ", a, "pointr); -pointr a< max &array[0] ++pointr a = max - 1Python Coding Exercise: Write a function that takes three parameters: a 2-D array arr, a row location i, a column location j and returns a float representing the fraction of neighbors around arr [i,j] # write your function here:def find_frac(arr,i,j)://Required Functionvoid func(int array_1[],int array_2[],int size){ for(int i=0;i<size;i++){ if(array_2[i]>array_1[i]){ array_1[i]=array_2[i]; } } return;} //main function to test the function.int main(){ int size=6; int a[]={1,5,9,8,7,6}; int b[]={1,4,10,12,7,15}; printf("First array before function call: "); for(int i=0;i<size;i++){ printf("%d ",a[i]); } func(a,b,size); //call to the created function printf("\nFirst array after function call: "); for(int i=0;i<size;i++){ printf("%d ",a[i]); } return 0;} 1. Write the statements to do the following: write a prototype for your function in the previous problem write a main function which includes the following steps declare two arrays of ints with 25 elements each prompt the user and read values into both arrays call your function from the previous problem print both arrays
- using namespace std; int main() { // Declare a named constant for array size here // Declare array here // Use this integer variable as your loop index int loopIndex; // Use this variable to store the batting average input by user double battingAverage; // Use these variables to store the minimim and maximum values double min, max; // Use these variables to store the total and the average double total, average; // Write a loop to get batting averages from user and assign to array cout << "Enter a batting average: "; cin >> battingAverage; // Assign value to array // Assign the first element in the array to be the minimum and the maximum min = averages[0]; max = averages[0]; // Start out your total with the value of the first element in the array total = averages[0]; // Write a loop here to access array values starting with averages[1] // Within the loop test for…One dimension array in C:Create an array of 100 integer elements and initialize the array elements to zero.Populate the array (using a for loop) with the values 10,20,30,..., 990,1000.Write code (using for loops) to sum all the elements and output the sum to the screen. without using #definePrint the elements of the array ‘a’ using the mentioned notations: int a[]={1,2,3,4,5}; int *p; p = a; for (int i = 0; i< 5; i++) { //Subscript notation with name of array //Subscript notation with pointer 'p' //Offset notation using array name //Offset notation using pointer 'p' }
- Programming c //undertanding arrays#include <stdio.h> int main(){int a[]= {100,200,250,375,-56};//size of array is5printf("%d\n",a[2]); //250printf("%d\n",a[5]);//??????wrong indexprintf("%d\n",2*a[4]);//-112a[3]=a[3]+200;printf("%4d%4d%4d%4d%4d", a[0],a[2],a[1],a[3],a[4]);//100 250 200 575 -56return 0;}C++ Find 2D array max and min. Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMiles.Ex: If the input is:-10 20 30 40the output is:Min miles: -10 Max miles: 40 #include <iostream>using namespace std; int main() { const int NUM_ROWS = 2; const int NUM_COLS = 2; int milesTracker[NUM_ROWS][NUM_COLS]; int i; int j; int maxMiles = 0; // Assign with first element in milesTracker before loop int minMiles = 0; // Assign with first element in milesTracker before loop int value; for (i = 0; i < NUM_ROWS; i++){ for (j = 0; j < NUM_COLS; j++){ cin >> value; milesTracker[i][j] = value; } } for(i = 0; i <= NUM_ROWS; i++) { for(j = 1; j <= i; j++) { cout << ""; } } cout << "Min miles: " << minMiles << endl; cout << "Max miles: " << maxMiles << endl; return…You are given an array of integers and you have to swap the first and last element of the array without using a third variable. Modify the original array and do not create a new array. Time: O(1) Space: O(1) Language: C You need not write the complete code, complete the function, void modify(int *arr, int n){ }
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