Determine the enthalpy of reaction for HCI(g) + NaNO2(s) → HNO2(1) + NaCI(s) 2NACI(s) + H2O(1) → 2HCI(g) + Na,0(s) AH° = -507.1 kJ/mol NO(g) + NO2(g) + Na,0(s) → 2NANO2(s) AH° = -427.0 kJ/mol NO(g) + NO2(g) → N20(g) + O,(g) AH° = -43.01 kJ/mol 2HNO2(1) → N20(g) + O2(g) + H20(I) AH° = +34.02 kJ/mol %3D %3D %3D

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Question 9 of 24
Determine the enthalpy of reaction for
HCI(g) + NaNO2(s) → HNO2(1) + NaCI(s)
2NACI(s) + H2O(1) → 2HCI(g) + Na20(s)
AH° = -507.1 kJ/mol
NO(g) + NO2(g) + Na,0(s) → 2NANO2(s)
AH° = -427.0 kJ/mol
NO(g) + NO2(g) → N20(g) + O2(g) AH°
= -43.01 kJ/mol
2HNO2(1) → N,0(g) + O2(g) + H2O(1) AH°
= +34.02 kJ/mol
%3D
%3D
%3D
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Transcribed Image Text:Question 9 of 24 Determine the enthalpy of reaction for HCI(g) + NaNO2(s) → HNO2(1) + NaCI(s) 2NACI(s) + H2O(1) → 2HCI(g) + Na20(s) AH° = -507.1 kJ/mol NO(g) + NO2(g) + Na,0(s) → 2NANO2(s) AH° = -427.0 kJ/mol NO(g) + NO2(g) → N20(g) + O2(g) AH° = -43.01 kJ/mol 2HNO2(1) → N,0(g) + O2(g) + H2O(1) AH° = +34.02 kJ/mol %3D %3D %3D Tap here or pull up for additional resources @ #3 24 & 2 8.
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