Determine an expression for the acceleration of each block for the case when the blocks have different masses, but the heavier block 1 (mass m) is positioned higher than the light one. Express your answer in terms of the variables m1, m2, and gravitational constant g a = Part D Determine the force that the string exerts on each block for the case when the blocks have different masses, but the heavier block 1 (mass m1) is positioned higher than the light one. Express your answer in terms of the variables m1, m2, and gravitational constant g. ? T =

Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one block with mass m1 = 12.25 kg is on a horizontal table and the other block with mass m2 = 7.5 kg hangs vertically. Both blocks experience gravity and the tension force, T. Use the coordinate system specified in the diagram. a.)  Assuming friction forces are negligible, write an expression, using only the variables provided, for the acceleration that the block of mass m1 experiences in the x-direction. Your answer should involve the tension, T. b.)  Under the same assumptions, write an expression for the acceleration, a2, the block of mass m2 experiences in the y-direction. Your answer should be in terms of the tension, T and m2. c.) Carefully consider how the accelerations a1 and a2 are related. Solve for the magnitude of the acceleration, a1, of the block of mass m1, in meters per square second. d.)Find the magnitude of the tension in the rope, T, in newtons.

O We know that the motion of the blocks is caused by the gravitational force acting on the hanging mass(m₁). Based on this, select all of the correct Newton's Second Law equations shown below. O Fnet = m₂a M2 Fnet = mig = (m₁ + m₂)a Fnet =m₁a M1 O Fnet = (m₁ + m₂)(a₁ + a₂)

Tommy is working on a physics problem and asks his friend Sarah to check his work. He is to draw a free body diagram for a man walking to the left and comes up with the following: He reasons, “The man is walking to the left, so the force of friction is acting in the opposite direction. The normal force should be opposite and equal to that of the gravitational force.” Is Tommy correct with his diagram and reasoning? If so, explain. If not, what mistake did he make? Communication throughout the test will also be evaluated on 1) rounding using significant digits, 2) proper use of units, 3) organization and neatness, and 4) showing all work