Design a BJT amplifier that meets the following specifications. Specifications: Voltage gains: A, mid= V JV;= -73, A mid= VJV,= -55 Input resistance: Z = 2455 N Load resistance: 3.3 kM Input signal: 1 mV peak Lower cutoff frequencies: fis= 103 Hz, fic=38 Hz and fLe= 750 Hz Higher cutoff frequencies: fui = 278 kHz and fito = 2.73 MHz

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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14V
C- 5pF
C = 8pF
C= 12pF
wi
C = 40pF
be
C= 8pF
ce
R,
Re
Cc
He
V,
0.82k2
ww
B = 120
Cs
+
3.3kN
RE
CE
Z,
Transcribed Image Text:14V C- 5pF C = 8pF C= 12pF wi C = 40pF be C= 8pF ce R, Re Cc He V, 0.82k2 ww B = 120 Cs + 3.3kN RE CE Z,
Problem 2:
Design a BJT amplifier that meets the following specifications.
Specifications:
Voltage gains: A, mid = VJV;= -73, Ays mid = VJV;= -55
Input resistance: Z; = 2455 N
Load resistance: 3.3 kM
Input signal: 1 mV peak
Lower cutoff frequencies: fis= 103 Hz, fic= 38 Hz and fLe= 750 Hz
Higher cutoff frequencies: fi = 278 kHz and fto = 2.73 MHz
Transcribed Image Text:Problem 2: Design a BJT amplifier that meets the following specifications. Specifications: Voltage gains: A, mid = VJV;= -73, Ays mid = VJV;= -55 Input resistance: Z; = 2455 N Load resistance: 3.3 kM Input signal: 1 mV peak Lower cutoff frequencies: fis= 103 Hz, fic= 38 Hz and fLe= 750 Hz Higher cutoff frequencies: fi = 278 kHz and fto = 2.73 MHz
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