deformation (y) to the point at which necking begins (Ers) may be approximated by a = Ke". The constant values K and n vary by alloy and also depend on the condition of the material (e.g. %CW, heat-treatment, etc. - more details later). The parameter n is often termed the strain- hardening exponent and has a value less than one. Find the tensile toughness for a metal alloy with modulus of elasticity of 103 GPa. Assume the plastic deformation begins at a strain value of 0.007 and fracture occurs at a strain value of 0.60. Assume also that fracture occurs at the point where necking begins and that the K and n values are 1520 MPa and 0.15 respectively.

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FRACTURE TOUGHNESS

(ii) The turbine blade root is found to contain a surface fatigue crack of 3.3 mm during a routine maintenance inspection. The major stop-start load cycle is experienced twice per day with a minimum stress of 34 MPa and a maximum stress of 195 MPa. The turbine blade has a KIC of 75 MPa√m. Fatigue crack growth rate data for this alloy is given by: the Paris law constant, A = 4.5 x 10-11 and the Paris law exponent, m = 3.8. How many more stop-starts would you recommend be used? Explain your reasoning. You can assume the shape factor Q = 1.2, K is in MPaNm and a (crack length) is in m

For a large plate, the geometry factor, f, is 1.03. Suppose a steel casting alloy has a critical fracture toughness of 78,886 psi*in1/2. The steel will be exposed to a stress of 40,295 psi during service. Calculate the minimum size of an edge crack that will grow. Repeat the calculation for Al2O3 with a fracture toughness of 1,600 psi*in1/2. How many times larger is the minimum size edge crack in the steel versus the alumina?

Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. Select one: The tensile yield strength Sy = 100 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 150 Mpa and the maximum strength Smax = 200 Mpa. The tensile yield strength Sy = 240 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 80 Mpa and the maximum strength Smax = 250 Mpa.

1. A part made of Aluminum 6061-T6 has a yield strength  = 400 MPa. For each stress state below, draw all 3 Mohr's circles, find the principal stresses, and calculate the safety factor against yield using both the distortion-energy (von Mises) and maximum shear stress (Tresca) criterions. (If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. You can use the fprintf() command in MATLAB to format numerical results A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications?

Estimate the linear relationship between the Ultimate Tensile Strength and HBN for the range of brass alloy shown in Figure 4b (ii).

What would be the compressive stress in MPa developed in the silica glass furnace tube constrained in the way illustrated in the figure if it were heated to 1000C?

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