A nylon material has a fracture toughness K1c = 2.1 MPa.m1/2 It follows a Paris Law for fatigue with a crack growth rate: A = C(AK)* The value of C = 4 x 108 and n 3.2 when AK is in MPa.m1/2 and da/dN is in m/cycle. A sample of this nylon is tested in tensile fatigue with an R ratio of 0. It has initial defects of size a; oriented perpendicular to the applied tensile stress. Assume the value of Y is 1.0 The sample is 25mm wide and 5mm thick. The maximum force in each cycle is 2,387 N. If the sample fails after 63,387 cycles, what size was a;? Enter your value in microns (x 106 m), as an integer, but without units. You have a margin of error of 3%.

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A: Solution:

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.