A nylon material has a fracture toughness K1c = 2.1 MPa.m1/2 It follows a Paris Law for fatigue with a crack growth rate: A = C(AK)* The value of C = 4 x 108 and n 3.2 when AK is in MPa.m1/2 and da/dN is in m/cycle. A sample of this nylon is tested in tensile fatigue with an R ratio of 0. It has initial defects of size a; oriented perpendicular to the applied tensile stress. Assume the value of Y is 1.0 The sample is 25mm wide and 5mm thick. The maximum force in each cycle is 2,387 N. If the sample fails after 63,387 cycles, what size was a;? Enter your value in microns (x 106 m), as an integer, but without units. You have a margin of error of 3%.

Elements Of Electromagnetics
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FRACTURE TOUGHNESS

A nylon material has a fracture toughness K1c = 2.1 MPa.m1/2
It follows a Paris Law for fatigue with a crack growth rate:
N = C(AK)"
The value of C = 4 x 10-8 andn = 3.2 when AK is in MPa.m1/2 and da/dN is in m/cycle.
A sample of this nylon is tested in tensile fatigue with an R ratio of 0. It has initial defects of size a; oriented perpendicular to the applied tensile stress. Assume the value of
Y is 1.0
The sample is 25mm wide and 5mm thick. The maximum force in each cycle is 2,387 N.
If the sample fails after 63,387 cycles, what size was a;?
Enter your value in microns (x 10-6 m), as an integer, but without units. You have a margin of error of 3%.
Transcribed Image Text:A nylon material has a fracture toughness K1c = 2.1 MPa.m1/2 It follows a Paris Law for fatigue with a crack growth rate: N = C(AK)" The value of C = 4 x 10-8 andn = 3.2 when AK is in MPa.m1/2 and da/dN is in m/cycle. A sample of this nylon is tested in tensile fatigue with an R ratio of 0. It has initial defects of size a; oriented perpendicular to the applied tensile stress. Assume the value of Y is 1.0 The sample is 25mm wide and 5mm thick. The maximum force in each cycle is 2,387 N. If the sample fails after 63,387 cycles, what size was a;? Enter your value in microns (x 10-6 m), as an integer, but without units. You have a margin of error of 3%.
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