Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Decrypt these messages that were encrypted using the Caesar cipher.
a) EOXH MHDQV
b) WHVW WRGDB
c) HDW GLP VXP
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- Use the RSA cipher with public key n = 713 = 23 · 31 and e = 43. Decrypt the given ciphertext and find the original message. (Assume the letters of the alphabet are encoded as follows: A = 01, B = 02, C = 03, ..., Z = 26.) Decrypt: 476 089 048 129arrow_forwardDetermine, if possible, the affine cipher C = aP + b (mod 26) that sends plaintext "OK" to ciphertext "HI."arrow_forwardApply the affine cipher formula C=(5P + 2) mod 26 to encript "LASER PRINTER". JGNSA DUNTXNA JSNAS DNUTXAN JGSAN DNUTXAN JGSAN DUNXANTarrow_forward
- Decrypt the message CFEJFE which was encrypted using the affine cipher: Alphabet: A = 0, B = 1,..., Z = 25 Message: f(p) = (15p+5) mod 26arrow_forwarda. Given p=23, q=7, and e=5, generate the public key (n,e) and the private key (n,d) using RSA Key generation algorithm. b. Given Bob's public key of (85, 7) and private key of (85, 55), show how Alice can encrypt m=7 to send to Bob. Show the ciphertext. c. Given Bob's public key of (85, 7) and private key of (85, 55), show how Bob can decrypt the ciphertext y=8 received from Alice. Show the plaintext. d. Using the fast exponentiation method (page 182), determine 535 mod 47arrow_forwardDecode the number using the given private key. Decode the number M = 38 using the private key d = 17 and n = 77. Assume you are decoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation.arrow_forward
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