Encode the number using the given public key. Encode the number M = 14 using the public key n = 77 and e = 13. Assume you are encoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation. 0000 a ano 46 (mod 77), encoded number = 46 47 (mod 77), encoded number = 47 48 (mod 77), encoded number = 48 49 (mod 77), encoded number = 49

Please recheck and provide clear and complete step-by-step solution in scanned handwriting or computerized output

(Hill Cipher) Decrypt the following cipher text: YZZN Using the key K =

Encrypt the message "destroy" by translating the letters into numbers, applying the given encryption function f(x) = (11x+16) mod 26, and then translating the numbers back into letters.   please do not provide solution in image format thank you!

Encrypt the message " MATH " by translating the letters into numbers and then applying the encryption function given, and then translating the numbers II back into letters. (a) f(p) = (17p+ 3) mod 26 (b) f(p) = (5p +14) mod 26 (c) f(p) = (19p+ 4) mod 26 Use A = 0,B = 1,C = 2,D = 3,E = 4,F = 5,G = 6,H = 7,1 = 8, J = 9, K = 10,L = 11,M = 12,N = 13,0 = 14,P = 15,Q = 16,R = 17, S = 18, T = 19,U = 20,V = 21,W = 22,X = 23,Y = 24,Z = 25 %3D %3D

You are doing a Diffie-Hellman-Merkle key exchange with Bradley using generator 2 and prime 37. Your secret number is 13. Bradley sends you the value 4. Determine the shared secret key, Enter your inswer a an integer or decimal ninbes lianplek14.55172 Enter DNE for Does Not Esiat, f Infiely

Decode the number using the given private key. Decode the number M = 38 using the private key d = 17 and n = 77. Assume you are decoding the number using the RSA cryptosystem. Note: You can use the Modular Exponentiation calculator to help with the calculation.

Need help with these two Difficult Intro to Elementary Number Theory Homework problems.

An RSA cipher has public key pq = 65 and e = 7. 1.  Translate the message YES into its numeric equivalent, and use the formula C = Me (mod pq) to encrypt the message. 2. Decrypt the ciphertext 50  16 and translate the result into letters of the alphabet to discover the message. SHOW WORK, ALSO DONT USE AI. USE PENCIL AND PAPER. SHOW SOLUTIONS