While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back and forth in the breeze once every T = 6.8 seconds. T = 6.8 seconds a) Calculate the frequency of oscillation (in Hertz) of the chandelier. b) Calculate the angular frequency ω of the chandelier in radians/second. c) Determine the length L in meters of the chandelier.

For a record playing at 45 rpm, find the frequency and the angular velocity.  frequency =  angular velocity =

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 46 rev/s, and its tip has a tangential speed of 60 m/s. What is the length of the rotating string? Number Type your answer here Units Choose your answer here

A 17 gg audio compact disk has a diameter of 12 cm. The disk spins under a laser that reads encoded data. The first track to be read is 2.3 cm from the axis; as the disk plays, the laser scans tracks farther and farther from the center. The part of the disk directly under the read head moves at a constant 1.2 m/s. When a disk is inserted, it takes 2.4 s to spin up from rest. What is the torque of the motor?

A 3.05kg object hangs, at rest, on a 1.96m long string attached to the ceiling. A 120g object is fired with a speed of 8m/s at the 3.05kg object, and the two objects collide and stick together in a totally inelastic collision. Hint 1 Hint 2 A. Determine the maximum angle that the two objects swing after the collision. Express the angle in radians. 1.51 0 max x = 1.51 radians B. Write an equation for the angle of the string, as a function of time, t, and one or more numeric values. Assume that the collision occurs at t=0s. 0= 1.51 sin (2.34t) X

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A 3.72 kg iron box is suspended from a spring with a spring constant of k=18 N/m. The mass is pulled 0.35 m downward from its equilibrium position and allowed to oscillate. a) what will the angular velocity be for this iron box? b) with what period will the iron box oscillate?

A stone with mass m = 11 g at the end of a massless strand is swinging in a circle of radius R = 1.42 m with and angular velocity ω = 4 rad/s. a.)Write an expression for the velocity v of the stone. b.) Calculate the velocity of the stone, v in m/s. c. In order to travel in a circle, the direction the stones path must constantly be changing (curving inward). This constant change in direction towards the center of the circle is a center pointing acceleration called centripetal acceleration ac. Write an expression for the centripetal acceleration ac of the stone, in terms of the linear velocity.  d.) Calculate the centripetal acceleration of the stone, ac in m/s2.

Engineers are designing a system by which a falling mass m imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum (the figure (Figure 1)). There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s2. In the earth tests, when m is set to 13.0 kg and allowed to fall through 5.00 m, it gives 300.0 J of kinetic energy to the drum. If the system is operated on Mars, through what distance would the 13.0-kg mass have to fall to give the same amount of kinetic energy to the drum? How fast would the 13.0-kg mass be moving on Mars just as the drum gained 300.0 J of kinetic energy?

While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back and forth in the breeze once every T = 6.6 seconds. Frequency is = 1/6.6 Angular Velocity = 0.952 Length of the chandelier = 10.81 That evening, while hanging out in J.J Thompson's House O' Blues, you notice that (coincidentally) there is a chandelier identical in every way to the one at the Michelson exhibit except this one swings back and forth 0.11 seconds slower, so the period is T + 0.11 Seconds. Determine the acceleration due to gravity in m/s^2 at the club