Critical values for quick reference during this activity. Confidence level Critical value 0.90 z* = 1.645 0.95 z* = 1.960 0.99 z* = 2.576 %3D Jump to level1 In a poll of 1000 randomly selected voters in a local election, 326 voters were against fire department bond measures. What is the sample proportion p? Ex: 0.123: What is the margin of error m for the 99% confidence level? Ex: 0.123

Objective: Finding critical valuesThe critical value for a 80% confidence inverval for a one sample proportion with a sample size of 27 is 1.28 1.314 1.315 0.84

Plz help ASAP

#3 Use the given confidence interval to find the margin of error and the sample proportion. (0.629,0.659) E= (Type an integer or a decimal.) p%3(Type an integer or a decimal.) Type here to search ■ 直 0 F4 F5 F7 2 4.

Assume that all grade-point averages are to be standardized on a scale between 0 and 4. How many grade-point averages must be obtained so that the sample mean is within 0.005 of the population mean? Assume that a 95% range 4-0 confidence level is desired. If using the range rule of thumb, o can be estimated as =1. Does the sample size seem practical? 4 4

Critical values for quick reference during this activity. Confidence level Critical value 0.90 z* = 1.645 0.95 z* = 1.960 0.99 z* = 2.576 Jump to level 1 A poll for a statewide election has a margin of error of 2.22 percentage points. How many voters should be sampled for a 99% confidence interval? Round up to the nearest whole number. Ex: 1234 voters

Rock band The Rolling Stones have played scores of concerts in the last twenty years. For 30 randomly selected Rolling Stones concerts, the mean gross earnings is 2.89 million dollars. Part a) Assuming a population standard deviation gross earnings of 0.5 million dollars, obtain a 99% confidence interval for the mean gross earnings of all Rolling Stones concerts (in millions). Confidence interval: ( Part b) Which of the following is the correct interpretation for your answer in part (a)? U A. We can be 99% confident that the mean gross earnings for this sample of 30 Rolling Stones concerts lies in the interval O B. There is a 99% chance that the mean gross earnings of all Rolling Stones concerts lies in the interval O c. If we repeat the study many times, 99% of the calculated confidence intervals will contain the mean gross earning of all Rolling Stones concerts. O D. None of the above

A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?

Sleeping outlier: A simple random sample of ten college freshmen were asked how many hours of sleep they typically got per night. The results were 24, 8, 6.5, 6, 9, 8.5, 7.5, 6.5, 8.5, 9.5     The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 95% confidence interval for the mean amount of sleep from the remaining values. A 95% confidence interval for the mean amount of sleep from the remaining values is ___ < u < ___.

View Policies Current Attempt in Progress Social Networking Sites In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet regularly. Of the Internet users, 1054 use a social networking site.' Find a 99% confidence interval for each of the following proportions. Hampton, K., Goulet, L., Rainie, L., and Purcell, K., "Social Networking Sites and Our Lives," Pew Research Center, June 16, 2011. (a) Proportion of US adults who use the Internet regularly. Round your answers to three decimal places. to The 99% confidence interval is eTextbook and Media Hint (b) Proportion of US adult Internet users who use a social networking site 69°F Cloudy W ch