A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?

Find the margin of error for the​ 99% confidence interval used to estimate the population proportion.   In a clinical test with 1100 ​subjects, 25​% showed improvement from the treatment.

(0.24, 0.56) is a confidence interval for the proportion of people who liked a new soda flavor.  What was the sample proportion for those who did NOT like the new soda flavor? Type the exact answer as a decimal.

A study of 1907 traffic fatalities found that 725 were alcohol related. Suppose you want your 99% confidence interval to be accurate within 1% of the population portion, how many traffic fatalities would need to be in the study?

A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​ "great deal of​ confidence" or​ "quite a lot of​ confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Find an 80​% confidence interval and interpret it. The 80​% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is ____.

identify the t-score for a 90% confidence interval if the sample size is 31.        t=

A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 189 people in the sample are newspaper readers. Calculate a 95%-confidence interval for the percentage of people (age 18 and over) in that town who read newspapers.

Given this data: {4, 5, 8, 11, 16, 8},(a) Find the 90% confidence interval for the mean.(b) Interpret what does the interval mean?

A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a 95% confidence interval for the proportion of adults who have a Facebook page.

A physician's billing office conducted a random check of patient records and found that 36 of 50 patients had changed insurance plans within the past year. Construct a 90% confidence interval for the true proportion. (Round your answers to 4 decimal places.)  The 90% confidence interval is from     to    .