Create a flowchart for this Java program

import java.util.Scanner;/**   This program calculates the geometric and   harmonic progression for a number entered   by the user.*/public class Progression{   public static void main(String[] args)   {      Scanner keyboard = new Scanner (System.in);      System.out.println("This program will calculate " +                         "the geometric and harmonic " +                         "progression for the number " +                         "you enter.");      System.out.print("Enter an integer that is " +                       "greater than or equal to 1: ");      int input = keyboard.nextInt(); // Match the method calls with the methods you write      int geomAnswer = geometricRecursive(input);      double harmAnswer = harmonicRecursive(input);      System.out.println("Using recursion:");      System.out.println("The geometric progression of " +                         input + " is " + geomAnswer);      System.out.println("The harmonic progression of " +…

Java - Smallest Number

8) Now use the Rectangle class to complete the following tasks: - Create another object of the Rectangle class named box2 with a width of 100 and height of 50. Note that we are not specifying the x and y position for this Rectangle object. Hint: look at the different constructors) Display the properties of box2 (same as step 7 above). - Call the proper method to move box1 to a new location with x of 20, and y of 20. Call the proper method to change box2's dimension to have a width of 50 and a height of 30. Display the properties of box1 and box2. - Call the proper method to find the smallest intersection of box1 and box2 and store it in reference variable box3. - Calculate and display the area of box3. Hint: call proper methods to get the values of width and height of box3 before calculating the area. Display the properties of box3. 9) Sample output of the program is as follow: Output - 1213 Module2 (run) x run: box1: java.awt. Rectangle [x=10, y=10,width=40,height=30] box2: java.awt.…