CP13. When a copper wire is exposed to air at room temperature, it becomes coated with a black oxide, CuO. If the wire is heated above a certain temperature, the black oxide is converted to a red oxide,Cu2O. At a still higher temperature, the oxide coating disappears. Explain these observations in terms of the thermodynamics of the reactions: 2 CuO(s) → Cu2O(s) + ½ O2(g) Cu2O(s) → 2 Cu(s) + ½ O2(g) and estimate the temperatures at which the changes occur.
CP13. When a copper wire is exposed to air at room temperature, it becomes coated with a black oxide, CuO. If the wire is heated above a certain temperature, the black oxide is converted to a red oxide,Cu2O. At a still higher temperature, the oxide coating disappears. Explain these observations in terms of the thermodynamics of the reactions: 2 CuO(s) → Cu2O(s) + ½ O2(g) Cu2O(s) → 2 Cu(s) + ½ O2(g) and estimate the temperatures at which the changes occur.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![CP13. When a copper wire is exposed to air at room temperature, it becomes coated with a black oxide,
CuO. If the wire is heated above a certain temperature, the black oxide is converted to a red oxide,Cu2O.
At a still higher temperature, the oxide coating disappears. Explain these observations in terms of the
thermodynamics of the reactions:
2 CuO(s) → Cu2O(s) + ½ O2(g)
Cu2O(s) → 2 Cu(s) + ½ O2(g)
and estimate the temperatures at which the changes occur.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4edefef-712d-4552-b2ae-5b3933dd0f28%2F3f5b0003-5fc3-4c87-ada6-a473bf3c74c1%2Fougp7gq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:CP13. When a copper wire is exposed to air at room temperature, it becomes coated with a black oxide,
CuO. If the wire is heated above a certain temperature, the black oxide is converted to a red oxide,Cu2O.
At a still higher temperature, the oxide coating disappears. Explain these observations in terms of the
thermodynamics of the reactions:
2 CuO(s) → Cu2O(s) + ½ O2(g)
Cu2O(s) → 2 Cu(s) + ½ O2(g)
and estimate the temperatures at which the changes occur.
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