Correct Although the forward reaction is third order, the reverse is second order. Rate-study data In a study conducted at the same temperature, the following data for reaction producing nitrosyl bromide were collected. Initial [NO] Initial [Br₂] Initial rate (M) (M) Trial (M/s) 0.150 0.240 49 0.240 197 0.480 393 Part C 1 2 3 0.300 0.300 What is the rate of the reaction when the initial concentration of NO is 0.400 M and that of Br₂ is 0.235 M? Express your answer numerically. ▸ View Available Hint(s)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve Part C only
<2. Chemical Equilibrium
Linking Equilibrium and Kinetics
The generic reaction
has the following rate laws:
2A B
forward reaction: rate= |A²
reverse reaction: rate=k, [B]
where kr is the rate constant for the forward reaction and kr is the rate constant for
the reverse reaction. At equilibrium, the two rates are equal and so [A]² = k [B].
The equilibrium constant for a reaction is related by the law of mass action to the rate
constants for the forward and reverse reactions:
[B]
K₁=k
[A] ²
kr
Submit
✓ Correct
Although the forward reaction is third order, the reverse is second order.
Rate-study data
Trial
In a study conducted at the same temperature, the following data for reaction producing nitrosyl bromide were collected.
Initial [NO] Initial Br₂] Initial rate
(M) (M) (M/s)
0.240
0.240
0.150
0.300
0.300
49
197
0.480
393
Part C
Previous Answers
rate=
What is the rate of the reaction when the initial concentration of NO is 0.400 M and that of Br₂ is 0.235 M?
Express your answer numerically.
▸ View Available Hint(s)
Submit
V— ΑΣΦ
?
1
2
3
M/s
Transcribed Image Text:<2. Chemical Equilibrium Linking Equilibrium and Kinetics The generic reaction has the following rate laws: 2A B forward reaction: rate= |A² reverse reaction: rate=k, [B] where kr is the rate constant for the forward reaction and kr is the rate constant for the reverse reaction. At equilibrium, the two rates are equal and so [A]² = k [B]. The equilibrium constant for a reaction is related by the law of mass action to the rate constants for the forward and reverse reactions: [B] K₁=k [A] ² kr Submit ✓ Correct Although the forward reaction is third order, the reverse is second order. Rate-study data Trial In a study conducted at the same temperature, the following data for reaction producing nitrosyl bromide were collected. Initial [NO] Initial Br₂] Initial rate (M) (M) (M/s) 0.240 0.240 0.150 0.300 0.300 49 197 0.480 393 Part C Previous Answers rate= What is the rate of the reaction when the initial concentration of NO is 0.400 M and that of Br₂ is 0.235 M? Express your answer numerically. ▸ View Available Hint(s) Submit V— ΑΣΦ ? 1 2 3 M/s
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