Consider two pendulums with lengths l1 and I2 performing simple harmonic motion. The first pendulum swings back and forth 10 times per minute, and the second one swings back and forth 300 times per hour. How would you find the ratio /|ll2? Select one: a. Use the conditions above to directly calculate l1/l2 by dividing 10 by 300. b. Use the conditions above to directly calculate l1/l2 by dividing 300 by 10. c. Calculate periods for each of the pendulums using the same units and then use the expression for the period of a simple pendulum to find /1/l2.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Consider two pendulums with lengths I1 and I2 performing simple harmonic motion. The first pendulum swings back and forth 10 times
per minute, and the second one swings back and forth 300 times per hour. How would you find the ratio //l½?
Select one:
a. Use the conditions above to directly calculate l /l2 by dividing 10 by 300.
b. Use the conditions above to directly calculate l1/l2 by dividing 300 by 10.
c. Calculate periods for each of the pendulums using the same units and then use the expression for the period of a simple pendulum
to find I1/l2.
Transcribed Image Text:Consider two pendulums with lengths I1 and I2 performing simple harmonic motion. The first pendulum swings back and forth 10 times per minute, and the second one swings back and forth 300 times per hour. How would you find the ratio //l½? Select one: a. Use the conditions above to directly calculate l /l2 by dividing 10 by 300. b. Use the conditions above to directly calculate l1/l2 by dividing 300 by 10. c. Calculate periods for each of the pendulums using the same units and then use the expression for the period of a simple pendulum to find I1/l2.
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