Consider two pendulums with lengths l1 and I2 performing simple harmonic motion. The first pendulum swings back and forth 10 times per minute, and the second one swings back and forth 300 times per hour. How would you find the ratio /|ll2? Select one: a. Use the conditions above to directly calculate l1/l2 by dividing 10 by 300. b. Use the conditions above to directly calculate l1/l2 by dividing 300 by 10. c. Calculate periods for each of the pendulums using the same units and then use the expression for the period of a simple pendulum to find /1/l2.

A pendulum has a period of 5.8 s.  If you were to transfer this pendulum to the surface of Mars (where g is 3.71 meters per second squared), what would the period (in seconds) be?

I am having a hard time finding the meaning of what T2 is in the equation. Do I just square the T or do something else? Thanks for the help in advanced.

For Parts I and II, use the pendulum equation and solve to predict the length needed for a pendulum with a period of 1 s and 2 s respectively. Use a piece of string (or thread, dental floss, shoe lace, etc.) and a steel nut (or washer or something small but with enough mass to weigh down the string) to build each pendulum. Time each pendulum for 30 periods and then find the average time for one period. Remember, a period is the time to complete one cycle of motion, out and back. Tape each pendulum up in perhaps a doorway where it is stationary and has room to swing. Be precise with your measuring and timing. Show your work. Part I Given: T = 1.00 s l =? Part II Given: T = 2.00 s l =?