Consider the system shown in Figure 1, where G(s) = a) If the unit step response of the closed-loop system is given in Figure 2, determine the values of ẞ and K. b) Calculate settling time for the closed-loop system achieved in part (a). 33+5+1 R(s) c) Given K 15, find the value of ẞ to make the closed- loop system critically damped, with settling time of 1. Determine the transfer function of the obtained closed-loop system. d) Given K = 4, calculate the steady state error of the closed-loop system for inputs 5u(t) and 5tu(t) separately, where u(t) is the unit step signal. 0.6061 0.556 y(t) Note: Y(S)- K G(s) Figure 1. ([s] Figure 2 = Π w1-32 Ts=%OS= 100.c-/√1-(<= -In(%OS/100) 2+1n2(%0S/100)

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R(s)
K
Y(s)
G(s)
Consider the system shown in Figure 1, where G(s) = 2+s+1
a) If the unit step response of the closed-loop
system is given in Figure 2, determine the values
of ẞ and K.
b) Calculate settling time for the closed-loop system
achieved in part (a).
c) Given K =
15, find the value of ẞ to make the closed-
loop system critically damped, with settling time of 1.
Determine the transfer function of the
obtained closed-loop system.
d) Given K = 4, calculate the steady state error
of the closed-loop system for inputs 5u(t)
and 5tu(t) separately, where u(t) is the unit
step signal.
0.6061
0.556
y(t)
Note:
Tp
=
77
-
Figure 1
1[s]
Figure 2
521
Ts=%OS= 100.e-1√1-(3-
-In(%OS/100)
=
2+1n2(%0S/100)
Transcribed Image Text:R(s) K Y(s) G(s) Consider the system shown in Figure 1, where G(s) = 2+s+1 a) If the unit step response of the closed-loop system is given in Figure 2, determine the values of ẞ and K. b) Calculate settling time for the closed-loop system achieved in part (a). c) Given K = 15, find the value of ẞ to make the closed- loop system critically damped, with settling time of 1. Determine the transfer function of the obtained closed-loop system. d) Given K = 4, calculate the steady state error of the closed-loop system for inputs 5u(t) and 5tu(t) separately, where u(t) is the unit step signal. 0.6061 0.556 y(t) Note: Tp = 77 - Figure 1 1[s] Figure 2 521 Ts=%OS= 100.e-1√1-(3- -In(%OS/100) = 2+1n2(%0S/100)
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