Consider the following system of linear equations.4x-2y z 145x+2z = 262x +y=-3Solve the system by completing the steps below to produce a reduced row-echelon form.R₁, R₂, and R3 denote the first, second, and third rows, respectively.The arrow notation (→) stands for "replaces," where the expression on the left of the arrow replaces the expression on theright.Here is the augmented matrix:Enter the missing coefficients for the row operations.(1)(2)(3)(4)R₁ R₁:(-5) R₁ + R₂ R₂:R₁ + R3 R3:R₂ → R₂:( 2 ) +•R₂ + R₁ R₁:4 - 2 -15022 1R₂ + R3 → R₂:1521O110-|C011201-|C2120 2102 4131310214-|--IN-|41321101426-37126N17- 1072175- 1025 55 552617840108X (2)(3)(4)(5)(6)(-5) R₁ + R₂ R₂:Solution:R₁ + R₂ R3:(1)-R₂(-¾ )R₂ → R₂:x =R₂ + R₁ R₁:R₂ + R3 R3:R₂ R3:•R3 + R₁ → R₁ :R₂ + R₂ → R₂:0y = 00101N/U01100 2001 00 1120012z =1 0 0-0S|N253901010130011011413421101413101Enter the missing coefficient for the row operation, fill in the missing matrixentries, and give the solution.N26517582172- 1072175- 105175845

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Consider the following system of linear equations. 4x-2y -z = 14 +2z = 26 =-3 5x 2x +y Solve the system by completing the steps below to produce a reduced row-echelon form. R₁, R₂, and R3 denote the first, second, and third rows, respectively. The arrow notation (→) stands for "replaces," where the expression on the left of the arrow replaces the expression on the right.