1.1Either redraw (it does not need to be perfect) or print the image below:2.(i) Shade in the quadrilateral DABCE.(ii) Shade in the triangle ACFE.BRecall Thales' 4 Theorems:1. Vertical angles are equal2. The angle sum of a triangle equals two right angles3. The base angles of an isosceles triangle are equal.4. An angle inscribed in a semicircle is a right angle.a)In figures a) and b) solve for a while only using Thales' four theorems. In your solution, briefly state thesteps that you took (include which theorems you used).В'F30°(iii) Label angle ZBAE as I.(iv) Label angle ZAED as y.ZDFC=30°, x=

Answered: Image /qna-images/answer/705a1255-de10-4fe3-8f73-4964c70896fd.jpg

1. Either redraw (it does not need to be perfect) or print the image below: B (i) Shade in the quadrilateral DABCE. (ii) Shade in the triangle ACFE. (iii) Label angle ZBAE as r. (iv) Label angle ZAED as y.

1. Either redraw (it does not need to be perfect) or print the image below: B (i) Shade in the quadrilateral DABCE. (ii) Shade in the triangle ACFE. (iii) Label angle ZBAE as r. (iv) Label angle ZAED as y.

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter4: Quadrilaterals

Section4.3: The Rectangle, Square, And Rhombus

Problem 42E: a Argue that the midpoint of the hypotenuse of a right triangle is equidistant from the three...

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Question

1.1
Either redraw (it does not need to be perfect) or print the image below:
2.
(i) Shade in the quadrilateral DABCE.
(ii) Shade in the triangle ACFE.
B
Recall Thales' 4 Theorems:
1. Vertical angles are equal
2. The angle sum of a triangle equals two right angles
3. The base angles of an isosceles triangle are equal.
4. An angle inscribed in a semicircle is a right angle.
a)
In figures a) and b) solve for a while only using Thales' four theorems. In your solution, briefly state the
steps that you took (include which theorems you used).
В'
F
30°
(iii) Label angle ZBAE as I.
(iv) Label angle ZAED as y.
ZDFC=30°, x=<BAF
C
b)
A
30°
C
ZCAO=30*, x =ZBCO
O is the circle center
B

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