Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Question
Consider the following set of processes, with the length of the CPU burst and I/O burst given in milliseconds:
Process | CPU, I/O, CPU | Arrival time |
P1 | 2, 3, 1 | 0 |
P2 | 2, 1, 4 | 4 |
P3 | 1, 1, 4 | 10 |
P4 | 6, 6, 6 | 13 |
For example: In FCFS a process p1 arrived at 0 ms gets CPU for 2 ms, then releases CPU to the next process for 3ms where it performs I/O burst and return back to the queue with a new arrival time as (2+3 = 5ms) 5 ms.
In case of a tie, go with process number. Perform the following for FCFS and non-preemptive SJF scheduling
- Calculate the average waiting time, average turnaround time.
- With respect to each metric justify which scheduling algorithm is good for the given process mix.
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- Suppose that we have the table below that includes four processes with their Arrival times and Burst times, and a Round Robin of time quantum 1 millisecond to be used for CPU scheduling. Answer the following questions: Process Arrival CPU-burst ID time time P1 0 1 P2 3 3 P3 2 4 P4 4 3 Completion Time Response Turn Around Time Time Waiting Time a. Draw the Gantt chart. b. Complete the above table. c. Calculate the average waiting time.arrow_forwardConsider the following set of 5 processes, with the length of the CPU-burst time given in milliseconds arriving at time 0: P1, P2, P3, P4, and P5 with corresponding burst time: 20, 47, 13, 17 and 22. The processes are assumed to have arrived in the order P1, P2, P3, P4, P5, all at time 0. a. Calculate average waiting time for First Come First Serve and None Preemptive Shortest Job First CPU scheduling algorithms. b. Which of the schedules in part a results in the minimal average waiting time (over all processes)?arrow_forward
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