Consider the following half-reactions: Cl2(9) + 2e - 2cF (ag) = 1. %3D I2(9) + 2e - → 21 (aq) E, = 0. %3D Pb2*(ag) + 2e → Pb(s) Eo = - 0 Crs*(og) + 3e→ Cris) Ea = -

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.87QP: Calculate the cell potential of a cell operating with the following reaction at 25C, in which [MnO4]...
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Which species is the strongest oxidizing agent, why? And which is the strongest reducing agent, why?

Consider the following half-reactions:
Cl2(g) 2e 2cI (ag)
Eo = 1.36 V
%3D
I2G) • 2e 21 (aq)
I2(g) *
Eo= 0.535 V
%3D
Pb* + 2e →
(aq)
Pb(s)
Eo = - 0.126 V
Cr3* (ag) + 3e Cres)
Cr(s)
Eo = - 0.74 V
2+
Mg (ag) + 2e →
Mg(s)
E, = -2.375 V
Transcribed Image Text:Consider the following half-reactions: Cl2(g) 2e 2cI (ag) Eo = 1.36 V %3D I2G) • 2e 21 (aq) I2(g) * Eo= 0.535 V %3D Pb* + 2e → (aq) Pb(s) Eo = - 0.126 V Cr3* (ag) + 3e Cres) Cr(s) Eo = - 0.74 V 2+ Mg (ag) + 2e → Mg(s) E, = -2.375 V
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