Consider the diagram of the forces acting on the block. The magnitude of the force labelled F₁ is 40.0 N. The magnitude of the force labelled F2 is 85.0 N. The distances labelled are x=0.600 m, y2 =0.40 m and y₁=1.100 m. What is the net couple moment on the block due to these forces? Give your answer in Nm to 1 decimal place. If the answer is negative include a negative sign in your answer. If the answer is positive do NOT include a positive sign in your answer.

Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F, =20 N, F2 =30N, F3 =5 N, F4 =25N, F5 = 20N & F6 =10N. The angles 02 =25°, 03 =30° , 04 = 40°, 06 = 45 ° (ENTER ONLY THE VALUES WITH TWO DECIMALS IN THE BOx PROVIDED BY REFERRING THE UNIT GIVEN IN BRACKET) F2 F3 F4 F1 F6 Fs (1) The horizontal component H of the given system (unit is in N) = (2) The Vertical component 2V of the given system (unit is in N) = (3) The resultant of the given force system is (unit in N) = (4) The direction of Resultant is (degrees) =.

Add the following forces to find the resultant force. V1 = 150 g @ 470 V2 = 550 @ 324° V3 = 350 g @ 215° V4 = 250 @ 172° V5 = 450 g @ 285°

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