Find the magnitude and direction of the resultant force for the system of forces shown in the figure. Where F, =20 N, F2 =30N, F3 =5 N, F4 =25N, F5 = 20N & F6 =10N. The angles 02 =25°, 03 =30°, e4 = 40°, e6 = 45 ° (ENTER ONLY THE VALUES WITH TWO DECIMALS IN THE BOX PROVIDED BY REFERRING THE UNIT GIVEN IN BRACKET) F2 F3 F4 F1 AF6 F5 (1) The horizontal component H of the given system (unit is in N) = (2) The Vertical component 2V of the given system (unit is in N) = (3) The resultant of the given force system is (unit in N) = (4) The direction of Resultant is (degrees) %3D

From the given figure, shown determine the moment at point A. The unit for Force is in pounds(lbs) and Length is in inches(in). F=3,557 N=2,446 M=5,251 P=8,018 Note: 1. Input the numerical value of your final answer in the box provided do not include the unit. 2. Use 2 Decimal Places in your final answer. 3. If your answer is negative, include the negative sign in inputting to the box provided. N. 1 in A 1 in

According To F1=600N,F2=800N and F3=400N for the forces acting on the drawbar in the figure; Find the angle 0 required for the vertical component of the resultant force to be 432N and calculate the directional cosines of the resultant

can you show steps and write steps clearly

a) What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30 50 Cable C 3 ft Cable D b) Using the figure above, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB And TC From part a. you do not need to derive them again for this part.

The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively .  A force of F= 120 N,  which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand  .   Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength  F M b) Calculate  the angle θ of the joint reaction force F J with the horizontal.…

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The forces acting on the arm in the figure and the angles they make with the axes are given. Accordingly, find the force F2 that must be applied for the resultant force to be 900 N in the -x-axis direction and the angle θ it makes with the -y- axis .

Find the magnitude and direction of the resultant for system of forces shown in the figure. 30° 60N 50° 35° 60N 80N

НОМE WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B.C (x, y., z) 2. Find Fas und FAC 3. Find Tanl and Iracl 4. Find FAg = F UA and Fac = F UAC 5- Finally find R and a, B.y 3m Fc= 500N FB= 500N 3m 5m 3m B 2m 4m 5m