Color in a species of minnows is determined by a single locus with two alleles:  D and d. DD individuals are dark, Dd are intermediate, and dd are pale. In a population that is in Hardy–Weinberg equilibrium, we count 29 pale minnows out of 93. How many minnows do you expect to be dark

In a population of 199 individuals, a locus has two alleles: E and e. If 33 individuals have the ee genotype, and the locus is at Hardy-Weinberg equilibrium, what is the frequency of the EE genotype? Round your answer to the second decimal place. Your Answer:

A population of 1000 beetles has 600 individuals that have genotype QQ, 100 individuals that have genotype Qq, and 300 individuals that have genotype qq.   a) Calculate f(Q) and f(q) for this population. Show your work and don’t assume HWE.       b) Calculate f(QQ), f(Qq), and f(qq) for this population. Show your work and don’t assume HWE.       c) Calculate the expected genotype frequencies if the population is in Hardy-Weinberg equilibrium. Show your work.       d) Does this population appear to be at Hardy-Weinberg equilibrium? Why or why not? (Although answering this question rigorously would require a statistical test, you don’t need to do that here.).

You are studying a population of mice in a field that have black (genotype BB), dark brown, (Bb) or light brown (bb) fur.   In your population you have 49 black individuals, 274 dark brown and 206 light brown.   What is the frequency of the B allele in the population? (round to 2 decimal places)

In a given population on a distant planet, there are 20 red, 25 orange, and 15 yellow creatures. Use Hardy-Weinberg equations and a chi square analysis to determine whether or not this population is in Hardy-Weinberg equilibrium. Show all work. Be sure to state a null hypothesis and explain your conclusion.

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

In mice, the waltzing allele (w) that causes the mouse to run in circles due to an inner ear defect is recessive to the non-waltzing allele (W).In an ideal mouse population exhibiting Hardy–Weinberg equilibrium of 150 mice, 50% of the alleles are non-waltzing. What is the frequency of the recessive allele?Record your answer as a whole number percentage.

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33

The frequency of a recessive allele in a population is 40%. What variable in the Hardy Weinberg equations does the 40% refer to? Why?

The UNF penguin lab decided to study the elusive polka dot penguin of Patagonia. They trapped a majority of the population using gummy worms as bait and collected the following information. Observed Genotype Frequencies (not in HWE) AA: 0.464 Aa: 0.427 aa: 0.109 If this population was in Hardy-Weinberg Equilibrium, what would be the expected genotype frequency for the heterozygotes? Retain 3 decimal places.