A population of wild roses has the following genotype frequencies for presence/absence of thorns: TT = 0.6 (large thorns), Tt = 0.2 (small thorns), tt = 0.2 (no thorns). What are the expected genotype frequencies for this gene in this population, and is this population currently in Hardy-Weinberg equilibrium?   TT = 0.6, Tt = 0.2, tt = 0.2; in equilibrium   TT = 0.49, Tt = 0.42, tt = 0.09; in equilibrium   TT = 0.6, Tt = 0.2, tt = 0.2; not in equilibrium   TT = 0.49, Tt = 0.42, tt = 0.09; not in equilibrium

Approximately 1% of the magpies (Pica pica) in a hypothetical populations are albino. Assume that the albino phenotype is due to a recessive allele and that this population is in HardyWeinberg proportions at this locus.   (a)  What is the estimated frequency of the albino allele in this population?  (b) What is the probability that the first progeny born to a mating between an albino and a normal magpie from this population will be albino? (Hint: what is the probability that the normal magpie is heterozygous, given the allele frequencies in this population?)

In a certain population in the US, the frequency of CCR5-Δ32 homozygous individuals is 1%. Assuming genetic equilibrium, what is the frequency of heterozygotes in this population?

Considering the Hardy-Weinberg theorem’s assumptions, which of the following statements is NOT correct?  (Recall that there are certain assumptions that must be true in order for the Hardy-Weinberg theorem to accurately predict genotype ratios in the next generation.)a) The population must be very large so there random genetic drift will not occur.b) No natural selection can occur.c) Mating must be random.d) Individuals must migrate into and out of the population so that gene flow will occur.e) Mutations must not occur.

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33

In a population with two alleles at the R locus (R and r), the frequency of the genotype rr is 0.10. Assuming that the R locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Rr)? Round and report your answer to the second decimal place (0.00).