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Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,..9 val a1 = #1 L2; hd(a1); #1 a2; hd a3; val a2 val a3 val a4 to get 1, combine the above val aa = hd(#1 (hd(#1 L2))); (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2

Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,..9 val a1 = #1 L2; hd(a1); #1 a2; hd a3; val a2 val a3 val a4 to get 1, combine the above val aa = hd(#1 (hd(#1 L2))); (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,...9 val a1 val a2 val a3 = #1 a2; #1 L2; hd(a1); val a4 = hd a3; to get 1, combine the above val aa = hd(#1 (hd(#1 L2))); (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2
Transcribed Image Text:Challenging, beyond recursion practice in this class, just an exercise to dissect hybird structure of tuples and lists val L1 = [1, 2, 3, 4, 5, 6, 7]; val L2 = ([([1,2],3), ([4,5,6],7)], (8,9)); Construct the following by ONE expression try ::nil style instead of [] Hint: try one at a time, figure out expressions for 1,2,...9 val a1 val a2 val a3 = #1 a2; #1 L2; hd(a1); val a4 = hd a3; to get 1, combine the above val aa = hd(#1 (hd(#1 L2))); (1) [(3,6), (4,2)] from L1 (2) ([2], (3,[5])) from L1 (3) [2,3,5] from L2 (4) (8,4,2,1) from L2
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