College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Cavendish determined that the gravitational constant was equal to 6.67x10-11 N m2/kg2. The Earth's radius is 6.37x106 m.
A 5.00 kg object feels a gravitational force of 49.0 N near the surface of the Earth (as you know).
The mass of the earth is 5.98x10^_________ kg. (Give the exponent.)
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- 29. Consider Planet X whose mass and radius are 9.05 x 1025 [kg] and 5.95 x 104 [m], respectively. If the weight of the object on the surface of the Earth is 2940 [N], what is its weight at height 750 [m] from the surface of the Planet X? Note: The gravitational constant is G = : 6.6743 x 10-11 m3 A. 3.70 × 108 [N] C. 4.99 x 108 [N] B. 4.88 x 108 [N] D. 5.12 x 108 [N] Lkgarrow_forwardThe gravitational acceleration constant gx on Planet X can be approximated by determining the acceleration of an object assuming Newton's Law of Universal Gravitation. If gx = 3.8 m/s^2 , G = 6.7 x 10^-11 Nm^2/kg^2, and Planet X's radius is 4000 km, what is the approximate mass of planet X? Give answer in kg.arrow_forwardThe acceleration due to gravity of planet X is 7.80m/s2, and its radius is 5,900 km. The gravitational constant is ?=6.67×10−11m2kg−1s−2. The mass of planet X is close to:arrow_forward
- Help me to solve this problem step by step and give answer as a 3 significant figuresarrow_forwardWhat is the magnitude of the gravitational acceleration at a height of two earth radius (2RE) above earth surface? Take gravitational acceleration near Earth surface as 9.81 m/s2. Express your answer in m/s2 and enter numerical value only, no unitsarrow_forwardA 4.4 kg mass weighs 35.64 N on the surfaceof a planet similar to Earth. The radius ofthis planet is roughly 6 × 10^6 m.Calculate the mass of of this planet. Thevalue of the universal gravitational constantis 6.67259 × 10^−11 N · m^2/kg^2.Answer in units of kg. Calculate the average density of this planet.Answer in units of kg/m^3.arrow_forward
- The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 9.16 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.arrow_forwardScientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.4 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What is the force of attraction between Mars and the satellite? 2.)What speed should the satellite have to be in a perfectly circular orbit? 3.)How much time does it take the satellite to complete one revolution?arrow_forwardThe International Space Station is in a 210-mile-high orbit. What is the station's orbital speed? The radius of Earth is 6.37×10^6 m, its mass is 5.98×10^24kg. Express your answer with the appropriate units. What is the station's orbital period? Express your answer in minutes.arrow_forward
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