Calculate your dilution strategyto make a 625 ng/mLHRP solution from a 12.5 μg/mL stock given the totalvolume of enzyme youwillneed for your condition this week. Note if you are testing pH, you only need to calculate one enzyme dilution because all other pHs will use the same strategy.
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Calculate your dilution strategyto make a 625 ng/mLHRP solution from a 12.5 μg/mL stock given the totalvolume of enzyme youwillneed for your condition this week. Note if you are testing pH, you only need to calculate one enzyme dilution because all other pHs will use the same strategy.
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- Given the following information, calculate the total activity in the undiluted protein sample. Activity of 1 ml of diluted sample = 0.5 Total volume of sample = 5 ml Dilution factor = 10 25 50.5 250 2.5A purified protein sample was used in a reaction, resulting in an activity of 696.7 nmol min-1. The reaction volume was 145.0 µL and the final volume before loading the plate was 1,050 µL. The total reaction time was 4.25 min. The amount of protein used in the reaction was 4.270 µg. Calculate the specific activity of the sample (in nmol min-1 µg-1).Size Size Crude Anion Cation 2) Exclusion Exclusion Lysate Exchange Exchange 1 2 Total Protein Concentration 15.2 6.6 2 3.75 4.7 (mg/mL) Final Sample Volume 60 30 20 4 3 (mL) Enzyme Specific Activity 0.43 1.7 7.25 18.3 12.5 (units/mgprotein) Based on your protein purification sample data, in which of the purification steps in your protocol did you effectively purify your enzyme? Select all that apply. a) anion exchange correct b) cation exchange correct c) size exclusion 1 correct d) size exclusion 2
- If 287.9 umol of enzyme X has a Vmax = 47.8 mmol/sec, what is the value of kcat %3D sec-1? Please report answer with 1 decimal place. Please do not report units. Your Answer: Answer units MacBook Air 888 F5 F4 F3 F2 %23 %24 %24What is the rate of the reaction at 20 sec for each of the enzyme concentration. Show calculationCalculate the Km of the enzyme with these parameters. kcat = 130s^-1 Vo = 3.0 μMs-1 S = 10 μM Et = 0.09 µM
- What would be the best buffering agent to choose if you wanted to buffer an enzyme reaction or tissue culture medium at pH = 7.95? Group of answer choices a. HEPES (4-(2-hydroxyethyl)-1-piperazineethanesulfonic acid); pK = 7.5 b. Histidine; pK1= 1.78; pK2= 5.97; pK3= 8.97 c. Bicarbonate; pK = 6.1 d. Phosphate; pK1 =2.0, pK2 = 6.8; pK3 = 12.5 e. Tris or Tris(hydroxymethyl)aminomethane; pK = 8.07You are asked to prepare HEPES buffered saline with the following constituents: НЕРES 10mM KCI 5mM NaCl 135mM CaCl2 1mM M9SO4 0.6mM Glucose 6mM You have previously made up 100 mM stock solutions of HEPES, KCI, CaCl2, and M9SO4 and a 1M stock of NaCl. The MW of glucose is 180.16 g/mol What volume of HEPES would you require to make up 400ml of buffer?You have a stock solution containing 1.5 mM of substrate in borate buffer pH 9.5. You transfer 1.25 mL of this stock into a cuvette and then add 250 µl of enzyme solution to initiate the reaction. What will be the final concentration of substrate in the cuvette following addition of the enzyme? 1.5 mM 1.25 mM 0.0075 mM 7.5 mM 1250 mM
- You have been provided with stock solutions of: stock A: 0.06 M sodium pyrophosphate buffer pH 8.5 stock B: 3 M ethanol stock C: 0.015 M NAD+ stock D: milli Q water Determine the volume you will need of each solution to prepare a buffer of with a final volume of 60 mL containing 10 mM sodium pyrophosphate pH 8.5, 100 mM ethanol, 1 mM NAD+. i.e. volume of stock A = _________mL volume of stock B = _________mL volume of stock C = _________mL volume of stock D = _________mL Show your calculations to arrive at your answers.How do I calculate the final concentration? I just need one solution to walk through the steps. Prepare eight standards of glucose with your 1 mM glucose solution, each with a final volume of 10 mL. Complete the table on the next page, indicating what your final concentration of glucose will be for each standard, in mM. Volume of Potassium Ferrocyanide Solution Volume of Enzyme Solution Volume of 1 mM glucose solution Final volume of solution Final Concentration of glucose in final solution (mM) 2.50 mL 1.00 mL 0.00 mL 10.00 mL 2.50 mL 1.00 mL 0.50 mL 10.00 mL 2.50 mL 1.00 mL 1.00 mL 10.00 mL 2.50 mL 1.00 mL 2.00 mL 10.00 mL 2.50 mL 1.00 mL 3.00 mL 10.00 mL 2.50 mL 1.00 mL 4.00 mL 10.00 mL 2.50 mL 1.00 mL 5.00 mL 10.00 mL 2.50 mL 1.00 mL 6.00 mL 10.00 mLAbsorbance of urea for a diabetic patient is 0.335 while 0.214 is the absorbance of standard kit for the same test, calculate the concentration of this test ? Concentration of standard kit = 50 mg/dl. Repl...