Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Calculate the vapor pressure (in torr) of a solution prepared by dissolving 0.693 mol of a non-volatile solute in 284 g of hexane (86.2 g/mol) at 49.6°C. P°hexane = 400.0 torr at 49.6°C. Report your answer to the tenths place.
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Step 1
Molar mass of hexane , C6H14 is = 6*12 + 14*1 = 86 g / mol
No . of moles of hexane , n = mass / Molar mass
= 284 g / 86 g / mol
= 3.30 mol
No . of moles of non-volatile solute , n' = 0.693mol
Total no . of moles , N = n+ n'
= 3.993 mol
Mole fraction of solute , X = n' / N
= 0.173
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