Calculate the energies, in Joules, of the v = 0, 1, 2, and 3 vibrational states for HCI (osc = 2991 cm-1) and 12 (˜osc = 214.5 cm-1). Make a sketch of the energy levels on the same scale
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- The force constants for ¹H₂ and 79 Br2 are 575 and 246 N-m¹, respectively. The atomic masses for ¹H₂ and 79Br2 are 1.0078 amu and 78.9183 amu, respectively. ▼ ▼ Part F Calculate the ratio of the vibrational state populations n₁/no for 79Br2 at 1190. K. Express your answer to three significant figures. n₁/no = 0.452 Submit Previous Answers Request Answer ΑΣΦ Part G X Incorrect; Try Again; 5 attempts remaining Calculate the ratio of the vibrational state populations no/no for 79Br2 at 280. K. Express your answer to three significant figures. Submit VE ΑΣΦ n2/mo= 0.9679 PRZ Previous Answers Request Answer ?14.44) The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below then lowest excited singlet electronic level at 77 K. Calculate the ratio of the population in these two states. [Hint: The Boltzmann equation is given by N2/N1 = (g2/g1 exp(-ΔE/kBT), where g1 and g2 are the degeneracies for level 1 and 2.]The first five vibrational energy levels of ¹H¹27 I are at 1144.83, 3374.90, 5525.51, 7596.66, and 9588.35 cm¹. Treating the molecule as an anharmonic oscillator, estimate the dissociation energy of the molecule in units of reciprocal centimetres (cm-¹). [Note: m(¹H) = 1.0078 u, m(¹271) = 126.9045 u; assume the second order anharmonicity constant, Ye, to be zero.] [Note: Use graph paper in your answer.]
- 1. [10] Consider an adsorption band in the combined rotational-vibrational spectrum of a linear molecule, where the fundamental vibrational frequency involved in the observed band is 2325 cm-¹ and the rotational constant of the molecule is B=2.4 cm³. Say hypothetically, the specific selection rules for the rotational states are AJ = ±2. At what wave numbers would the first three peaks that occur at both higher and lower wave numbers than fundamental vibrational frequency occur at? What transitions would each peak correspond to?(4) Determine the vibrational contribution to Cy for one mole of HCN, where ₁ = 2041 cm-¹, v₂ = 712 cm ¹(doubly degenerate), and 3 = 3369 cm¹ at T=298 K, 500 K and T=1000 K.The equilibrium vibration frequency of the Iodine molecule is Us cm¹ and the an harmonicas constant -0.003 What is the intensity of hot band v=1→v=2 relative to that of the fundamental v=0-v-1, if the temperature is 300 °K ? .
- The three normal modes of water are the symmetric stretch (3652 cm¹), the antisymmetric stretch (3756 cm¹), and the bend (1595 cm¹). (a) Calculate the molecular vibrational partition function of water at 500 K. (b) At 500 K, what fraction of water molecules have the bend excited to v₂=1. What fraction of water molecules have the symmetric stretch excited to v₁=1? Why do more molecules have the bend excited? (c) At 500 K, what fraction of water molecules have both v2-1 and v₁=1 excited?Starting from the formula for the rotational energy levels: ħ² EJ J(J+1) = J = 0, 1, 2... 21 Show that: ħ² AE = 1/² (J+1) Δε J = 0,1,2...The lowest triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K. Calculate the ratio of populations in these two states at equilibrium. [Hint: The Boltzmann equation is given by N2/N1 = (92/91)exp(-AE/KBT), where g₁ and 92 are the degeneracies for levels 1 and 2.] N₂ N1
- The bond in 'H*Cl molecule and Ar2 is characterized by the force constant k 480 Nm-1 and k = 0.160 Nm-1. Assume that the molecule is described by a quan- tum harmonic oscillator. • What are the zero-point energies and the uncertainty in the bond length for these two molecules? • What will be the effect of deuteration (i.e., exchanging 'H with 2H) and the isotopic exchange of 35CI with 37CI on the zero point energy respectively if the force constant remains the same? Based on your result, determine the resolution of the spectrom- eter in cm- respectively in order to see the change by these two isotopic exchange and compare.Please try ur best to calculate and answer the last question in bold.The four lowest electronic levels of a Ti atom are: J = 2, 3, 4 and 1, at 0, 170, 387 and 6557 cm-1, respectively. There a many other electronic states at higher energies. The boiling point of Ti is 3287C. What are the relative populations of these levels at the boiling point if the degeneracy of levels is 2J + 1? Is the ground state most highly populated level?(b) The lowest three vibrational energy levels of 127|35CI lie at 191.77, 573.06, and 951.34 cm-1. Determine the force constant, zero-point energy, well- depth and bond dissociation energy for 127135CI.