C. Multiple Choice. A series RLC circuit has a resistance of 7.5 Q, a capacitance of 10-2F, an inductance of 1/6 H and an applied voltage E = 12 V. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
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Chapter24: Resistive-inductive-capacitive Parallel Circuits
Section: Chapter Questions
Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...
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Note!
-Answer only NO. 4 and 5
-Answers from 1 to 3 are C, D, and B, respectively.

C. Multiple Choice. A series RLC circuit has a resistance of 7.5 Q, a capacitance of 10-2 F, an
inductance of 1/6 H and an applied voltage E = 12 V. Assuming no initial current and
charge when voltage is first applied, find the subsequent current in the system.
1. What is the simplified linear ODE with constant coefficient from the problem?
(D² + 42D + 600)I = 0
C: (D² + 45D + 600)I = 0
D
None of the choices
A:
B:
(D² + 45D + 40/3)! = 0
2. What is the equation to solve for I of the system?
5/15
t + B2 sin
2
5V15
5V15
1 = e-45t (B, cos
I = e¬45/2t (B, cos-
5V15
-t + B2 sin
A:
C:
2
2
2
1 = e2 (B, cos-t+B2 sin-
SV15,
45
45
D
None of the choices
B:
2
3. What is the value of constant B,?
A:
-72
C:
45
B:
72
4. What is the value of constant B2?
-72
A:
C:
45
D
B:
72
5. What is the final equation to solve for the subsequent current of the system?
(48/15
|sin
25
( 48/15
5/15
5/15
A:
I = e-45t
I = e-45/2t
C:
25
Cos
2
2
5/15, (48/15
I = e2
45
D
B:
None of the choices
Cs,t
2
25
:
ÜA..
Ü A..
A ..
Transcribed Image Text:C. Multiple Choice. A series RLC circuit has a resistance of 7.5 Q, a capacitance of 10-2 F, an inductance of 1/6 H and an applied voltage E = 12 V. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system. 1. What is the simplified linear ODE with constant coefficient from the problem? (D² + 42D + 600)I = 0 C: (D² + 45D + 600)I = 0 D None of the choices A: B: (D² + 45D + 40/3)! = 0 2. What is the equation to solve for I of the system? 5/15 t + B2 sin 2 5V15 5V15 1 = e-45t (B, cos I = e¬45/2t (B, cos- 5V15 -t + B2 sin A: C: 2 2 2 1 = e2 (B, cos-t+B2 sin- SV15, 45 45 D None of the choices B: 2 3. What is the value of constant B,? A: -72 C: 45 B: 72 4. What is the value of constant B2? -72 A: C: 45 D B: 72 5. What is the final equation to solve for the subsequent current of the system? (48/15 |sin 25 ( 48/15 5/15 5/15 A: I = e-45t I = e-45/2t C: 25 Cos 2 2 5/15, (48/15 I = e2 45 D B: None of the choices Cs,t 2 25 : ÜA.. Ü A.. A ..
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