© 4Two 200x75x25.3 channels, back to back, as shown below, act as column of length 5m with pinned ends. Yield stress =250MPa, E=210GPa. [ コロ a (a) Use the formula with a buckling load of 100kN and calculate the maximum value of the clear spacing a between the channels. (35mm) (b) Use the Perry-Robertson formula given below to calculate the safe load the column can carry. Take the load factor=1.7 and a=120mm K.f₂=fy+(1+n)ƒe_[(fy 2 0.5 +(1+n)fe 2 2 = {yle] (771.9kN)

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.6.12P: AW310 × 74 wide-flange steel column with length L = 3.8 m is fixed at the base and free at the top...
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©
4Two 200x75x25.3 channels, back to back, as shown below, act as column of length 5m
with pinned ends. Yield stress =250MPa, E=210GPa.
[
コロ
a
(a) Use the formula with a buckling load of 100kN and calculate the maximum value of
the clear spacing a between the channels. (35mm)
(b) Use the Perry-Robertson formula given below to calculate the safe load the column
can carry. Take the load factor=1.7 and a=120mm
K.f₂=fy+(1+n)ƒe_[(fy
2
0.5
+(1+n)fe
2
2
= {yle]
(771.9kN)
Transcribed Image Text:© 4Two 200x75x25.3 channels, back to back, as shown below, act as column of length 5m with pinned ends. Yield stress =250MPa, E=210GPa. [ コロ a (a) Use the formula with a buckling load of 100kN and calculate the maximum value of the clear spacing a between the channels. (35mm) (b) Use the Perry-Robertson formula given below to calculate the safe load the column can carry. Take the load factor=1.7 and a=120mm K.f₂=fy+(1+n)ƒe_[(fy 2 0.5 +(1+n)fe 2 2 = {yle] (771.9kN)
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