Bobina and Bob are on the seesaw down at the elementary school playground and decide to see if they can move to the correct location to make the seesaw balance. Boina weighs 400. N and sits 2.00 m from the fulcrum. Where should bob sit to balance the seesaw? Bob weighs 450. N.

The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 24.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 24.0 N block. At what mark on the meter stick would you place a 19.0 N block to balance the 24.0 N block? mark: At what mark on the meter stick would you place a 44.0 N block to balance the 24.0 N block? mark:

A 13.6 kg. 3.6 m long seesaw bar (assume that the bar is uniform) is perfectly balanced upon a support that is 0.2 m to the left of its center. There is a 6.5 kg block sitting on the far right side of the seesaw. How large of a mass do we need to place on the far left of the seesaw for it to be balanced?

A gymnast with a mass of 54 kg stands on the end of a uniform balance beam as shown in the figure.  The beam is 5.50 m long and has a mass of 250 kg.  Each support is 0.54m from the end of the beam.  What is the force on the beam due to support 2?

1.0m 3.0m 0.5m mi m2 m, PA N, 5. The drawing above shows two objects on a board supported at two locations. The m = 40 kg (centered over P), m;=20 kg and m3=10 kg. b. Determine the magnitude of the torque exerted about point P by .. (don't forget to convert masses to forces.) i. mi ii. m2 ii. m3

A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum a distance ?=0.266 m from the rock, which has a mass of 325 kg, and fits one end of the rod under the rock's center of weight.

Questions 1. A uniform meter stick pivoted at its centre, has a 100.0 g mass suspended at the 25.0 cm position. At what position should a 75.0 g mass be suspended to put the system in equilibrium? Show workings. 1 m 75 cm 25 cm 50 cm 75.0 g 100.0 g I

Two kids are playing on a seesaw on the school playground. The first kid (of mass 50 kg) sits 2 meters from the fulcrum. The other child (who has a mass of 70 kg) sits on the other side of the seesaw. How far away from the fulcrum does the second child need to sit in order to balance the seesaw? Assume that the seesaw itself is weightless. O 0.79 m O 1.43 m O 1.03 m O 2.24 m

The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 25.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 25.0 N block.

A baseball bat balances 76.1 cm from one end. If a 0.500 kg glove is attached to that end, the balance point moves 26.7 cm toward the glove. $ % Part A Find the mass of the bat. mbat = Submit Provide Feedback 15. ΑΣΦ Search or type URL MacBook Pro Request Answer & 7 * 00 ? kg