Bleach we used is actually based on NaOCl solutions. Bleach in the bottle is 6% by weight The most concentrated solution used here is diluted 1:10. Use that information to calculate the molarity of NaOCl in each of the three solutions. Find the molarity of NaOCl for: 0.6% 0.45% 0.30%
Bleach we used is actually based on NaOCl solutions. Bleach in the bottle is 6% by weight The most concentrated solution used here is diluted 1:10. Use that information to calculate the molarity of NaOCl in each of the three solutions. Find the molarity of NaOCl for: 0.6% 0.45% 0.30%
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Bleach we used is actually based on NaOCl solutions. Bleach in the bottle is 6% by weight The most concentrated solution used here is diluted 1:10. Use that information to calculate the molarity of NaOCl in each of the three solutions.
Find the molarity of NaOCl for:
0.6%
0.45%
0.30%
Then find k with k’ = k[OCl-]^x.
if k' does not change, the reaction is zero-order in OCl- (x=0) if k' doubles, the reaction is first-order i n OCl- (x = l )
i f k' quadruples, the reaction is second-order in OCl- (x=2).
k' for .6% is .0075, .45% is .0044, .3% is .0028
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