MoodleVUTbelt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the beltremains the same at both ends of the inserted jockey pulley. Diameters are respectively m=700 mm forthe driven pulley and a 330 for the driver with a coefficient of friction of and 0.28 between the belt andeach pulley. Pulleys are mounted on parallel axes kept 1.257m apart. Angle 0 70° between the radius(tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drivesystem and calculate:The contact angles of the open belt drive (without the jockey pulley) are respectively 0d%3Drad on the driver side and 0mrad on the machine/driven side.%3DThe take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in amodified contact angle ofrad at the driver pulley.As a result of the reaction of of magnitde 100N due to the take-up pulley, the tensile force in the slack side ofthe belt is F2N and the tension in the tight side of the belt%3DN.The linear speed of the belt ism/s and a total power ofkW is transmitted.In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, thedistance between axes and the respective diameters remain the same. The take up pulley is removed. Analyzethe resulting the open belt drive and determine the corresponding tension in the tight side F.N under new conditions. The power transmitted by the new in the open belt arrangement isW One can conclude that using the take up pulley

Draw the diagram of the driver and driven pulley without the jakey pulley,

belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively the dnven pulley and a each pulley. Pulleys are mounted on parallel axes kept 1.25m apart. Angle 0 70° between the radius = 700 mm for =330 for the driver with a coefficient of friction of and 0.28 between the belt and (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively 0d %3D rad on the driver side and 0m rad on the machine/driven side. The take-un nulley keens th

belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively the dnven pulley and a each pulley. Pulleys are mounted on parallel axes kept 1.25m apart. Angle 0 70° between the radius = 700 mm for =330 for the driver with a coefficient of friction of and 0.28 between the belt and (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively 0d %3D rad on the driver side and 0m rad on the machine/driven side. The take-un nulley keens th

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

MoodleVUT
belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt
remains the same at both ends of the inserted jockey pulley. Diameters are respectively m=700 mm for
the driven pulley and a 330 for the driver with a coefficient of friction of and 0.28 between the belt and
each pulley. Pulleys are mounted on parallel axes kept 1.257m apart. Angle 0 70° between the radius
(tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive
system and calculate:
The contact angles of the open belt drive (without the jockey pulley) are respectively 0d
%3D
rad on the driver side and 0m
rad on the machine/driven side.
%3D
The take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in a
modified contact angle of
rad at the driver pulley.
As a result of the reaction of of magnitde 100N due to the take-up pulley, the tensile force in the slack side of
the belt is F2
N and the tension in the tight side of the belt
%3D
N.
The linear speed of the belt is
m/s and a total power of
kW is transmitted.
In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, the
distance between axes and the respective diameters remain the same. The take up pulley is removed. Analyze
the resulting the open belt drive and determine the corresponding tension in the tight side F.
N under new conditions. The power transmitted by the new in the open belt arrangement is
W One can conclude that using the take up pulley

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