Being able to identify where charge (postive and negative) is located within a molecule is useful in regards to understanding its chemical and physical behaviour Below is an amine, drag and drop charges, where appropriate on the molecule Hint consider the relative electronegativies of the bonding atoms Delta (6) symbols indicate partial charge (regions of localised charge, but not formal +ve or ve charge) H R R-C-N R 11 O (+) és H 8+

Being able to identify where charge (postive and negative) is located within a molecule is useful in regards to understanding its chemical and physical behaviour Below is an amine, drag and drop charges, where appropriate on the molecule Hint consider the relative electronegativies of the bonding atoms Delta (6) symbols indicate partial charge (regions of localised charge, but not formal +ve or ve charge) H R R-C-N R 11 O (+) és H 8+

Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter6: The Periodic Table And Periodic Law

Section6.3: Periodic Trends

Problem 21SSC

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2RO; (aq) + 12 H* (aq) + 3 M (s) = RO (g)+3M²* (aq) + 6 H2O (1) = 3.86 V. R: 5 valence e-, electronegativity of R = 3.3 M: 2 valence e-, electronegativity of M = 0.5 O and H represent Oxygen and Hydrogen (the known elements, with their known properties) All atoms follow the octet rule; except for Hydrogen which follows the duet rule. b) Calculate the new cell potential if concentrations of all the reactants is deceased to 0.5 M, and the concentrations of all the products is increased to 0.5 M. Assume 6 mol electrons transferred in the reaction.
2RO; (aq) + 12 H* (aq) + 3 M (s) = RO(g)+ 3M²* (aq) + 6 H2O (1) E°rxn = 3.86 V. R: 5 valence e-, electronegativity of R = 3.3 M: 2 valence e-, electronegativity of M = 0.5 O and H represent Oxygen and Hydrogen (the known elements, with their known properties) All atoms follow the octet rule; except for Hydrogen which follows the duet rule. Does the above reaction favour the forward or reverse direction? If the concentration of RO; (ag) was reduced and What is the pH of this reaction? explain the reasons for your answers.
estion 5 of 15 The first resonance structure of the thioformate ion, HCOS, is shown. -1 : H. Determine the correct second resonance structure of thioformate ion? O..0 ..-1 0=C=S-H -1 O..0 S=C=0-H 0:0 ..-1 C%3= ī.
2RO; (aq) + 12 H* (aq) + 3 M (s) = RO (g)+ 3M²* (aq) + 6 H2O (1) E°xn = 3.86 V. %3D R: 5 valence e-, electronegativity of R = 3.3 M: 2 valence e-, electronegativity of M = 0.5 O and H represent Oxygen and Hydrogen (the known elements, with their known properties) All atoms follow the octet rule; except for Hydrogen which follows the duet rule. b) 2RO; (aq) + 12 H* (aq) + 3 M (s) = RO (g) + 3M²* (aq) + 6 H2O (1). E°rxn = 3.86 V. Determine new cell potential if the concentration of the reactants is at 1 M and of all the concentrations of all the products was decreased to 0.78 M and the temperature was 53.33°F if 3 mol e transferred
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