Beam with a pin support at point A,roller support at pint B and the acting forces can be seen below. Determine the internal forces and moments at the mid point of BC section. (20 Points) 6 m 12 kN/m B 3 m 6 kN

3 For the beam shown, find the reactions at the supports and plot the shear-force and bending-moment diagrams. V = 9 kN, V2 = 9 kN, V3 = 200 mm, and V4 = 1100 mm. ATAT-V3 Provide values at all key points shown in the given shear-force and bending-moment diagrams. X (mm) B A = B = C = D = E= F= P = Q = E * KN * KN * KN × KN KN x KN ✩ kN.mm *kN.mm D 0.00 Reaction force R₁ (left) = In the shear-force and bending-moment diagrams given, +V 0.00 X (mm) 6.3 kN and reaction force R2 (right) = P 11.7 kN. Q 0.00

Need help please include all units and steps. Thanks

The column shown is fabricated from two C250 x 30 standard steel shapes (see Appendix B for its cross-sectional properties) that are oriented back-to-back with a gap of 33 mm between the two channels. The column is fixed at its base and free to translate in the y direction at its upper end. Translation in the z direction, however, is restrained at its upper end. A load P is applied at an offset distance of 430 mm from the channel flanges. Use the AISC equations given in Section 16.5, and assume that L = 4.1 m, s = 33 mm, E = 200 GPa, oy = 275 MPa, and (Gallow); = 145 MPa. Offset - distance e P Lateral bracing in z direction C250 x 30 L C250 x 30 Cross section.