Q6: Assume total number of addresses a CPU can manage are 12 bits long. a. What is the maximum size of memory if byte addressable? b. What is the maximum size of memory if word (2-byte long) addressable? If CPU uses left most 2 bits to interleave across RAM chips. How many maximum number of RAM chips it can support. C.

Q6: Assume total number of addresses a CPU can manage are 12 bits long. a. What is the maximum size of memory if byte addressable? b. What is the maximum size of memory if word (2-byte long) addressable? If CPU uses left most 2 bits to interleave across RAM chips. How many maximum number of RAM chips it can support. C.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In the given memory space; the number of Rows is equal to the number of Columns. Let the size of the Memory is 1024 bits; the minimum number of bits required for addressing one of the Rows is
Assume that a memory is initialised as follows: Memory Address Cell Contents 0x000336 0x38 0x000337 0x26 0x000338 0x48 0x000339 0x38 0x00C33A 0x00C33B 0x77 0x38 The following sequence of operations is executed in the given memory: Write(0x00C337, 0x0205) Write (0x00C339, 0x0106) Write(0x00C338, 0x0109) Assume that the read and write operations are done in groups of two bytes, and the system is a big endian system. What is the result of read(0x00C337) +read (0x00C338)? Write your answer in Base 10 (decimal)
6)This true or false Question from computer organizations Course,just write for me the final answer.
lets assume that CPU want to write a value 310 into a specific location of main memory. the 32 bit address of the location is lAC34045. Write all the steps that the CPU take to perform the write operation
5. How many bits are required to address a 4M X 16 main memory if a) main memory is byte addressable? b) main memory is word addressable? 6. How many bits are required to address a 1M X 8 main memory if a) main memory is byte addressable? b) main memory is word addressable?
Assume you now have 1kB of memory, i.e. the memory address space runs from 0 to 1023. The starting address of the first word is 0, the second word is 4, the third word is 8, and so on. The last word comprising 4 bytes resides in addresses 1020, 1021, 1022, 1023. Thus, the last word starts at 1020, which is a multiple of 4. Now assume the same 1kB of memory but now, word size is 64 bits. The starting address of the first word is 0, the second, third, and last word starts at? my answer: (correct) the second is equal to = 8 the third is equal to = 16 help me find the last word
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(b) The following Figure 2 illustrates the memory allocation with its content for a variable declared (MyValue) in word size. Adsress: Value: Address: Value: D1 AB 00406000: 00406006: 13 00406001: 02 00406007: 00406002: 39 00406008: OE 00406003: 00 00406009: CD 00406004: OE 0040600A: AB 00406005: CD 0040600B: 02 Figure 2 If the value of 02ABh from the memory needs to be loaded into an accumulator register, complete the following instruction to execute it. MOV , MyValue +
Assume that a memory is initialised as follows: Memory Address Cell Contents 0x000336 0x38 0x000337 0x26 0x000338 0x48 0x000339 0x38 0x00C33A 0x00C33B 0x77 0x38 The following sequence of operations is executed in the given memory: Write(0x00C337, 0x0205) Write (0x00C339, 0x0106) Write(0x00C338, 0x0109) Assume that the read and write operations are done in groups of two bytes, and the system is a big endian system. What is the result of read(0x00C337) +read (0x00C338)? Write your answer in Base 10 (decimal)