Attempt to rank the following compounds in order of decreasing carbonyl stretching frequency. In other words, rank the compound you think will have the highest carbonyl frequency as "1". CH3 HO, H. * Plkase explin 1740 1720 (M benzaldehyde acetophenone benzoic acid Но NH2 benzamide N-methylbenzamide salicylic acid oh oo d ob benzoic anhydride ethyl benzoate CF3 2,2,2-trifluoroacetophenone benzophenone

How many ¹H NMR signals are present in the product of the reaction shown below? O O 00 9 1) CH3MgCI 2) H₂O

Match each structure to the appropriate NMR by placing the letter of the compound in the box on the NMR it corresponds to. The aromatic region has been included as an inset to make splitting patterns easily visible.

10)Pyrrolium (1) and pyridinium (2) have markedly H different pK, values. Circle the compound with the lower pK₂ value. -N-H 11) The 1H NMR spectrum of phenol is shown below. Of note, the aryl proton signals resolve in this molecule. Assign protons to specific signals in the spectrum 8 7 6 H₂ H₁ 5 ppm H3 H₂ *CHCl3 2 H₁

looking at this reaction (first image),  The second image shows the 13C NMR spectrum of the 2-acetnaphthone which is the starting material and an 13C NMR spectrum obtained for the reaction product: Based a comparison of the two 13C NMR spectra, is product A or product B the major product of the reaction? - Explain your reasoning.

4-t-butylcyclohexanone was transformed to cis and trans-4-t-butylcyclohexanol using NaBH4. How can we tell that the trans isomer is prefered from the following NMRs? Make sure to explain why the product distribution occurs in the reaction. (PICTURE that says 1H is the same NMR just zoomed).

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Identify the structure of the unknown compound from the given spectra. The letters on the NMR indicate the splitting pattern.@GMU 2020 Integrations: OA OB OD OE 7 5 -- DOM ►

Draw the structures of Compound 13 a and 13b, clearly indicate your assignments of all proton resonances. Calculate the unsaturation index of each compound Compound 13a: C8H1002 A=7.17 ppm singlet 4h B=4.70 ppm singlet 4h C= 2.99 ppm singlet 2H 1)Excess CrO3, H2SO4 2) CH3OH (excess) , H+ heat Compound: C10H1004 A=8.11 ppm singlet 4H B=3.96 ppm singlet 6 H

Draw the product structure and label each unique hydrogen atom with a letter. Label the NMR spectral peaks with letters corresponding to each hydrogen atom.