Assume all diodes are identical and have VDo = 0.7V. Use the constant voltage drop method to solve for DC values. Assume D1 is off and D2 is on. With the diodes in these states and the +15V supply varies from +14V to +16V, solve for the following value: (AssumeID2pc = 100μA, n=2, and VT=25mVrd2=2,000 (not actual values)). Find the value for VoAG = ± _mV. (Round to the nearest whole number) D1 31кл -lov None of the choices 1,000 IDI O 714 143 O 750 ΙΚΩ 2V (1+) 1kQ2 2V 2k ID2 (+- 3V D2 +15V 2k

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Assume all diodes are identical and have VDO = 0.7V. Use the constant voltage drop method to
solve for DC values. Assume D1 is off and D2 is on. With the diodes in these states and the +15V
supply varies from +14V to +16V, solve for the following value: (AssumeID2Dc = 100μA, n=2, and
VT=25mVrd2=2,000 (not actual values)).
Find the value for VOAC =±_ _mV. (Round to the nearest whole number)
зікл
-lov
None of the choices
1,000
3145
O 714
143
O 750
1ΚΩ |
2V
ΙΚΩ
ww (it)
2V
(+1)
2k
(+-)
3V
+15V
ID2
D2
2k
Transcribed Image Text:Assume all diodes are identical and have VDO = 0.7V. Use the constant voltage drop method to solve for DC values. Assume D1 is off and D2 is on. With the diodes in these states and the +15V supply varies from +14V to +16V, solve for the following value: (AssumeID2Dc = 100μA, n=2, and VT=25mVrd2=2,000 (not actual values)). Find the value for VOAC =±_ _mV. (Round to the nearest whole number) зікл -lov None of the choices 1,000 3145 O 714 143 O 750 1ΚΩ | 2V ΙΚΩ ww (it) 2V (+1) 2k (+-) 3V +15V ID2 D2 2k
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