As a junior field engineer, you have been asked to assist a contractor in resolving the following problem A 4.9 kW motor and gear drive rated at 175 rpm has been shipped with the four impeller blades listed below. The baffled rapid mix tank to which one of the impellers will be installed is 3.0 m² in volume (1.56 m diameter and 1.56 m depth). Assume water temperature of 10C, G= 1000s, water density = 1000 kg/m³, and motor power to water power transfer efficiency of 80%. Impeller options: A. Axial flow, 3 blades, diameter = 0.48 m, N=1.0 B. Axial flow, 3 blades, diameter = 0.61 m, Np=1.0 C. Radial flow, 6 blades, diameter = 0.48 m, Np=6.3 D. Radial flow, 6 blades, diameter = 0.61 m, Np=6.3 Answer the following: a. What is the rotational speed (n) in rps? b. What is the power required in kW for impeller option A? What is the power required in kW for impeller option C? C. d. What is the power transferred to the water from the selected motor in kW? Which impeller should be used? (Select A, B, C, or D) e.

PROBLEM 3 An axial flow pump has the following data: Rotational speed 750 rpm Discharge of water 1.75m3/s Head 7.5m Hub to runner diameter ratio 0:45 Through flow velocity is 0.35 times the peripheral velocity. Find the diameter, and A. 7.11 m В. 7.3 m C. 1.5 m D. 0.59 m minimum speed ratio. А. 1.7 B. 0.83 С. 3.0 D. 4.01

Problem 1(5): A centrifugal pump transports water between two reservoirs. The pump has an outer diameter of 15 cm, an inner diameter of 8 cm, and a blade width of 2 cm and operates at 1750 rpm. If the water enters the pump axially at ẞ₁ = 45º¸ compute the volume flow rate, Problem 2(10): In the pump of problem 1, the water exits at B₂ 65° when the pump is driven at 1750 rpm. = Compute the minimum power required by the pump?

Given: Asked: Solution:

Example 3-6 A mixed type reaction turbine has D1= 3m and D1= 2.1m. Inlet and outlet Vane angle 60° & 150° respectively and thickness of 30 cm parallel to axis of rotation with guide vanes angle of 15° and a flow rate of 10 m/s . a) Calculate the required speed of the runner for smooth flow at inlet. b) If the velocity of flow remains constant and the discharge is radial find the power developed and the work done, also find the hydraulic losses, total head, and overall efficiency.

A static thrust stands as it showed in the Figure. The intake velocity is 200 m/s, exhaust velocity is 500 m/s, intake cross-section area 1 m, intake pressure is -22.5 kPa, and exhaust pressure is pressure and considered zero. Determine the anchoring force (Fth).( Density = 1.02kg / (m ^ 3))

A centrifugal pump impeller has an external diameter of 1.2 m and internal diameter of 0.8 m. The width of the impeller at outlet is 0.175 m and the blade angle at outlet is 65 degrees. The flow velocities at inlet and outlet are the same (Va1 = Va2). This pump delivers 1.55 m3/s of water at 210 rpm. For theoretical performance, calculate: 1-The flow velocity . 2-blade speed at outlet. 3-blade angle at inlet (in degrees). 4-the developed head. 5-The pressure rise across the impeller. 6-The number of blades . 7-The NPSH . %3D

can you please find the solution

Analyze to select the type of the turbine when its diameter is 600 mm, rotational speed is 600 rpm and working under a water head of 120 meters. The buckets deflect the 100 mm diameter jet through an angle of 165°. Take the coefficient of velocity for the nozzle as 0.97. Use Table given below for selection of turbine. Sr. # Specific speed (rpm) Type of turbine 1 8-30 Pelton wheel with one nozzle 30 - 50 Pelton wheel with 2 or more nozzles 50-250 Francis turbine 4 250-1000 Kaplan turbine 2. 3.

Problem-3: A centrifugal pump lifts water against a static head Az = EN m. The pipe setup has a constant diameter of 0.08 m, major losses in the suction side h, = EN3 m and in the discharge side hLD is 3 m. The pump impeller has a diameter of 0.15 m, exit width of 0.015 m, exit blade angle of 22° and speed of N = 20EN rpm. The hydraulic efficiency is 0.85. If the flow at the entrance is radial, find the discharge, pump head, atmospheric pressure Pat, Vapor pressure P, and maximum allowable height of the pump from the feeding tank water surface elevation if the pump is operating under T 25 °C at altitude H= 20EN m. %3D 0, = NPSHR/Hp =1.21×10³N = (P EN=62 Is-mx at-abs-P,)/Y-hLsT -0H, Pa-abs /Y = 10.33(1– 2.256x10-H)56 P,ly = e14.29-3985(T+233.4))