An object of height 11 cm is placed 44 cm in front of a converging lens with a focal length of 24 cm. What's the height of the image?

an object is placed 19.0 cm to the left of a lenss of the focal length 12.0cm. 27.0 cm to the right of this lens is a plane mirror. Where does the final image form?    - 5.56 cm to the right of the mirror -5.56 cm to the left of the mirro - 21.4 cm to the left of the lens -32.6 cm to the left of the lens -19.6 cm to the left of the mirror

On one side of a diverging lens of focal length 42.7 cm, you position an object of height 3.27 cm somewhere along the principal axis. The resultant image has a height of 1.31 cm. How far from the lens is the object located? 51.1 cm 63.9 cm O 102.2 cm O 89.5 cm

A converging lens causes an object 72.7 cm from the lens to create an image 61.7 cm from the lens on the opposite side of the lens. What is the focal length (in cm) of this lens?

A converging lens causes an object 58 cm from the lens to create an image 74.5 cm from the lens on the opposite side of the lens. What is the focal length (in cm) of this lens?

On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cm

An object is located 8.00 cm from a converging lens that has a focal length of 10.0 cm. The height of the object is 0.77 cm. What is the height h; of the image? h; = Number Units

An object is 60.0 cm from a converging lens and the object is 1.00 cm tall. What is the poisition and height of the image if the focal length of the lens is 25.0 cm? The object is at 0.0233 cm and the height of the image will be 0.715 cm upright. The object is at 0.0233 cm and the height of the image will be 0.000388 cm inverted. The object is at 42.9 cm and the height of the image will be 0.000388 cm upright. The object is at 42.9 cm and the height of the image will be 0.715 cm inverted.

A concave spherical mirror has a radius of curvature, R = 18.2 cm. If an object is placed 53.4 cm in front of the lens, what is the magnification of the image produced?

A person looks at a gem using a converging lens with a focal length of +8.7 cm. A virtual image is formed 55.3 cm from the lens. What is the magnification?