College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Two converging lenses are separated by 25.0 cm. The focal length of each lens is 12.0 cm. An object is placed 36.0 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right.
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- b) A lens forms an image of an object. The object is 16.0cm from the lens. The image is 12.0cm from the lens on the same side as the object. What is the focal length of the lens? Is the lens converging or diverging? thearrow_forwardNeeds Complete typed solution with 100 % accuracy.arrow_forwardIn a darkened room, a burning candle is placed 1.63 m from white wall. A lens is placed between candle and wall at a location that causes a larger, inverted image to form on the wall. When the lens is moved 86.6 cm toward the wall, another image of the candle is formed. K 1.63 m How far apart are the two object distances that produce these images? Answer in units of m. Find the focal length of the lens. Answer in units of m.arrow_forward
- A lens forms an image of an object. The object is 14.0 cm from the lens. The image is 17.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 9.20 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram.arrow_forwardA diverging lens has a focal length of magnitude 17.8 cm. (a) For an object distance of 44.5 cm, determine the following. What are the image distance and image location with respect to the lens? (Give the magnitude of the distance in cm.) image distance cm image location in front of the lens v Is the image real or virtual? virtual What is the magnification? Is the image upright or inverted? upright (b) For an object distance of p2 = 13.4 cm, determine the following. What are the image distance and image location with respect to the lens? (Give the magnitude of the distance in cm.) image distance cm image location in front of the lens v Is the image real or virtual? ---Select--- What is the magnification? Is the image upright or inverted? upright (c) For an object distance of p3 = 26.7 cm, determine the following. What are the image distance and image location with respect to the lens? (Give the magnitude of the distance in cm.) image distance cm image location in front of the lens v Is…arrow_forwardA contact lens is made of plastic with an index of refraction of 1.54. The lens has an outer radius of curvature of +1.95 cm and an inner radius of curvature of +2.47 cm. What is the focal length of the lens? cm Need Help? Read It Watch Itarrow_forward
- Two lenses, one converging of focal length 10.0 cm and one diverging of 5.0 cm, are placed 30.0cm apart. An object is placed 20.0 cm in front of the converging lens. Determine the location and magnification of the final image with respect to the original object.arrow_forwardA 5.87 mm high firefly sits on the axis of, and 12.5 cm in front of, the thin lens A, whose focal length is 6.05 cm. Behind lens A there is another thin lens, lens B, with a focal length of 23.7 cm. The two lenses share a common axis and are 60.7 cm apart. What is the height of this image? Express the answer as a positive number.arrow_forward7. A lighted candle is placed 40.0 cm in front of a diverging lens. The light passes through the diverging lens and on to a converging lens (f = 10.0 cm) that is placed 9.00 cm from the diverging lens. The final image is real, inverted, and 35.0 cm beyond the converging lens. Find the focal length of the diverging lens. cm 0 ssf6 ssf60 ssf 60 ssf607 ssf60arrow_forward
- A diverging lens has a focal length of magnitude 22.2cm. Find the magnification for the object at distance 44.4 cm. Find the magnification for the object at distance 22.2 cm. Find the magnification for the object at distance 11.1 cm.arrow_forwardWhen two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. s₁, y = 120,2.40 cm Submit Correct Set Up: Apply Solve: Lens 1: m₁ = Previous Answers Part B $1 f₁ $1-f₁ $₂,|y₂| = 1 S s' 1 S +1/1 = = gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm to each lens. m₁ 120 cm 60.0 cm = = -2.00 = Y'₁ Y1 120 cm and m2 $1…arrow_forwardConsider the optical system shown in the figure. The lens and mirror are separated by d = 1.00 m and have focal lengths of f₁ = +87.5 cm and f₂= = -53.4 cm, respectively. An object is placed p = 1.00 m to the left of the lens as shown. Lens LL -1.00 m Object distance location (a) What is the distance (in cm) and location of the final image formed by light that has gone through the lens twice? (Give the magnitude of the distance and select its location with respect to the lens.) ---Select--- -1.00 m- cm Mirror (b) Determine the overall magnification of the image. (c) State whether the image is upright or inverted. upright invertedarrow_forward
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