An iron block with a mass m¡ = m/s. It collides with a copper block whose mass is m2 = 9.20 kg. The collision is inelastic so the blocks stick together, due to Velcro on the surfaces of the blocks. After the collision, the blocks continue moving and compress a spring with a spring constant k = 5000 N/m. How many centimeters will the spring be compressed from its equilibrium position? 4.80 kg, is flying through the air with a speed of 7.50 m2 m1 wwl AX

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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An iron block with a mass mị =
m/s. It collides with a copper block whose mass is m2 =
inelastic so the blocks stick together, due to Velcro on the surfaces of the blocks. After
the collision, the blocks continue moving and compress a spring with a spring constant
k
4.80 kg, is flying through the air with a speed of 7.50
9.20 kg. The collision is
= 5000 N/m. How many centimeters will the spring be compressed from its
equilibrium position?
m2
m1
AX
Transcribed Image Text:An iron block with a mass mị = m/s. It collides with a copper block whose mass is m2 = inelastic so the blocks stick together, due to Velcro on the surfaces of the blocks. After the collision, the blocks continue moving and compress a spring with a spring constant k 4.80 kg, is flying through the air with a speed of 7.50 9.20 kg. The collision is = 5000 N/m. How many centimeters will the spring be compressed from its equilibrium position? m2 m1 AX
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