A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 149 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 77.0 cm, what was the speed of the bullet at impact with the block? Answer should be in m/s.

A 5.00-g bullet moving with an initial speed of vi = 450 m/s is fired into and passes through a 1.00-kg block as shown in the figure below. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with force constant 910 N/m. The block moves d 5.80 cm to the right after impact before being brought to rest by the spring. = (a) Find the speed at which the bullet emerges from the block. m/s w (b) Find the amount of initial kinetic energy of the bullet that is converted into internal energy in bullet-block system during the collision. J Need Help? Read It Master It

A tennis ball bouncing on a hard surface compresses and then rebounds. The details of the rebound are specified in tennis regulations. Tennis balls, to be acceptable for tournament play, must have a mass of 57.5 g. When dropped from a height of 2.5 m onto a concrete surface, a ball must rebound to a height of 1.4 m. During impact, the ball compresses by approximately 6 mm. If the ball accelerates uniformly when it hits the floor, what is its approximate acceleration as it comes to rest before rebounding?A. 1000 m/s2         B. 2000 m/s2C. 3000 m/s2         D. 4000 m/s2

A 0.150kg bullet is initially at rest 1.50m above the earth in a rifle which is aimed horizontally to the right. The rifle launch mechanism is a spring with a spring constant k=150.0N/m. The spring is initially compressed 0.150m from its equilibrium position with the bullet resting on the spring. The rifle barrel length is 1.35m from the spring equilibrium position. Using the isolated system model, what is the total energy of the bullet while at rest in the rifle chamber?