A moving particle encounters an external electric field that decreases its kinetic energy from 9450 eV to 6990 eV as the particle movesfrom position A to position B. The electric potential at A is -43.0 V, and that at B is +39.0 V. Determine the charge of the particle.Include the algebraic sign (+ or -) with your answer.Number iUnitsLowerpotentialHigherpotentialVBE SUBROL

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Answered: A moving particle encounters an…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I Review A 13.0 nC charge is at x = Ocm and a -1.4 nC charge is at = 3.0 cm Part A At what point or points on the a-axis is the electric potential zero? Express your answer in centimeters. If there is more than one answer, give each answer separated by a comma. Vα ΑΣφ ? x0 = cm Submit Request Answer
A dust particle with mass 5.0 ug and charge 2.0 nC starts from rest at point a and moves in a straight line to point b. a. Draw and explain the electric potential that the dust particle sees for this situation? b. What is it speed v at point b? 3.0 nC 1.0 cm 1.0 cm 1.0 cm -3.0 nC
b
A proton with an initial speed of 850,000 m/s is brought to rest by an electric field. ▾ Part A Did the proton move into a region of higher potential or lower potential? O Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. O Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. O Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. Submit ✓ Correct Here we learn how to determine the distribution of the electric potential based on the movement of a charged particle. Part B Previous Answers What was the potential difference…
Q1 A conductive sphere of radius 40 cm is charged with a total surface charge of (-2 nC) and held at a fixed position.. a) Find the electric potential at a radial distance of 20 cm. b) Sketch a graph of the electric potential (V) versus radial distance (r). c) From the shown figure of the charged sphere, If a small ball of mass (0.05 kg) that has 60 cm Q=-2nC A B a charge of (+1 μC) starts its motion from rest at point A of radial distance (80 cm) to point B of radial distance (60 cm). While you can the effect of gravity, ignore calculate the velocity of the small ball at point B. q=+1µC VA=0 m/s m => 0.05kg 80 cm R = 40 cm
In Figure 3, a thin plastic rod of length L = 0.12 m is located along the x-axis and charged uniformly with a charge Q = 56.0 C. Find the electric potential ratio (Vp1/Vp2) for point P, on the x-axis and for point P2 on the y-axis knowing that the distances are d = 0.05 m and D = 0.15 m.
During a particular thunderstorm, the electric potential between a cloud and the ground is Vcloud - Vground = 1.5 x 108 V, with the cloud being at the higher potential. What is the change in an electron's potential energy when the electron moves from the ground to the cloud? Number i Units
In the figure shown, which of the following gives the correct order of the electric potential, from largest to smallest? A B D 20 O A B. C. D O D, B, C, A O C, A. B, D O D, C. B, A
For the following electric field: E(x,y) = (x² + y²)î + 2xyŷ Calculate the potential in the xy plane. Assume the potential at the origin equals to zero, meaning (0,0) = 0. Select one: a. 4(x,y) = 3 -2xy2 ○ b. x(x, y) = - - xy c. y(x, y): == -x³-xy² ○ d. 2:3 (x, y): = - +xy² 3 e. (x, y) = x3 + xy² ○ f. (x, y): - 3 xy2 ×
Electrodynamics
I Review I Constants A 11.0 nC charge is at x = Ocm and a -1.3 nC charge is at x = 7 cm . Part A At what point or points on the x-axis is the electric potential zero? Express your answer using two significant figures. If there is more than one answer, give each answer separated by a comma. V ΑΣφ Xo = cm Submit Previous Answers Request Answer
In the figure (Figure 1), C1C1 = C5C5 = 8.1 μFμF and C2C2= C3C3 = C4C4 = 5.0 μFμF . The applied potential is VabVab = 200 VV .Calculate the charge on capacitor C2C2.Calculate the potential difference across capacitor C2C2.Calculate the charge on capacitor C3C3.Calculate the potential difference across capacitor C3C3.Calculate the charge on capacitor C4C4.Calculate the potential difference across capacitor C4C4.Calculate the charge on capacitor C5C5.Calculate the potential difference across capacitor C5C5.

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