An electron accelerates from rest through an electric field and into a magnetic field as shown in the diagram to the right. The plates have a potential difference of 85 V and the magnetic field has a magnitude of 0.75 T. (a) Calculate the initial speed of the electron upon entering the magnetic field. (b) Calculate the magnitude and direction of the magnetic force on the electron. (c) Calculate the radius of the electron’s circular path.

An electric field of 1.51 kV/m and a perpendicular magnetic field of 0.413 T act on a moving electron to produce no net force. What is the electron's speed?

A singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T.   (Note that the charge of an electron is e = 1.6 x 10−19 C.)   a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?

A proton moves perpendicular to the magnetic field of 0.5 T. The track is observed to be a circular arc of radius 2.0 cm. Find: a) The direction of the force acting on the proton? b) The velocity of the proton c) The kinetic energy of the moving proton d) The magnitude of the force acting on the proton

A long straight wire carries a 1.5 A current. An electron moves parallel to the wire at speed 1.3 x 104 m/s. The distance between the electron and the wire is 7 cm. Calculate the magnitude of the magnetic force on the electron.(Give your answer in newtons. Don't round your answer.)

A proton moves with a speed of 1.0 x 107 m/s in the directions shown. A 0.50 T magnetic field points in the positive x-direction. For each, what is the magnetic force on the proton? Give your answers as a magnitude and a direction.

Write down an expression for the force experienced by an electron moving with a velocity, v, in a magnetic field B. By equating this expression to the force required to cause electrons to follow a circular path of radius, r, derive an expression for the ratio, (?⁄?) for an electron in terms of the magnetic field strength, the radius of the circular path and the accelerating potential, V.

Determine the magnitude of the force on an electron traveling 5.85×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.20 T . Express your answer to two significant figures and include the appropriate units. Determine the direction of the force on an electron.

Starting from rest, an electron is accelerated through a region between two oppositely charged plates, as shown in Figure 1. The distance between the plates is 10 cm and the magnitude of the potential difference between them is 100 V. Immediately after exiting the region with the uniform electric field, the electron enters a region with a uniform magnetic field of 0.85 T, directed into the page. (a) Calculate the magnitude of the electric force on the electron. (b) Calculate the work done by the electric force on the electron. (c) Determine the electron's speed when it enters the magnetic field. (d) Determine the magnitude and direction of the magnetic force on the electron when it enters the magnetic field. (e) Suppose that the experiment was repeated with the locations of the positive and negative plates switched, and the electron was replaced with a proton, but nothing else was changed. Calculate R,/R., the ratio of the radius of the proton's path in the magnetic field (R,) to that…

An electron moves with a speed of  5.0×107 m/s in the directions shown in (Figure 1) and (Figure 2) below. A 0.40 T magnetic field points in the positive x-direction.What is the magnitude of the magnetic force in (Figure 2)?