College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.215 T. If the kinetic energy of the electron is 4.20 × 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μmarrow_forwardcan you please ans (a) (b) (c)?arrow_forwardA long straight wire carries a 1.5 A current. An electron moves parallel to the wire at speed 3.1 x 104 m/s. The distance between the electron and the wire is 8 cm. Calculate the magnitude of the magnetic force on the electron.(Give your answer in newtons but don't include the units.)arrow_forward
- See the attached figure for this problem. A charge of 9.26 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 2.94 T directed into the screen and an electric field of strength 6.76 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed?arrow_forwarda charged particle enters a mass spectrometer with uniform magnetic field B= .60 T pointing into the page. if the particle has mass m= 3.2 x10^-12 kg and is travelling at a speed of 5.0 x 10^5 m/s, then it is seen to curve in the magnetic field as shown and strikes a detector d=12.0 cm away from the point where it entered the mass spectrometer. what is the charge on the particle? a) +44 microC b) -44 microC c) -68 microC d) +68 microCarrow_forwardA beam of electrons moving with speed v = 2.6 × 10’m/s enter and then leave the rectangular region of the magnetic field, as shown below. The trajectory of electrons is a quarter of a circle of radius R= 0.020 m. Mass of electron m = 9.11 x 10-31 kg, charge of electron charge q = 1.6 × 10-19 C). The magnitude and direction of the magnetic field are: %3D %3D the region of the magnetic field a. 0.45 T, perpendicular to the page, into the page Ob. 0.74 T, perpendicular to the page, out of the page Oc. 0.45 T, perpendicular to the page, out of the page С. O d. 0.074 T, perpendicular to the page, into the page e. 0.68 T, perpendicular to he page, into the pagearrow_forward
- An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.280 T. If the kinetic energy of the electron is 2.60 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron X Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) the radius of the circular path X Your response differs from the correct answer by more than 10%. Double check your calculations. μmarrow_forwardProblem 5: An electron (q= -e = -1.60 × 10-19 C and me = 9.11 × 10-31 kg) in a cathode-ray tube is accelerated through a potential difference of 10 kV. Thus, the electron leaves the cathode-ray tube with a speed v = 5.93 × 107 m/sec. The electron then passes through the 2.0 cm wide region of uniform magnetic field (shown in the Figure above on the right). What field strength will deflect the electron by 10°? Answer: B = 0.0029 T. OV 10 kV 2.0 cm 10°arrow_forwardAn electron moves in a circular path perpendicular to a magnetic field of magnitude 0.240 T. If the kinetic energy of the electron is 4.10 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μmarrow_forward
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